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V125BC [204]
3 years ago
13

You spend $31 on hibachi and find the service to be great. You decide to tip

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

$6.20 savings.

Step-by-step explanation:

Thus, a product that normally costs $31 with a 20 percent discount will cost you $24.80, and you saved $6.20. You can also calculate how much you save by simply moving the period in 20.00 percent two spaces to the left, and then multiply the result by $31 as follows: $31 x . 20 = $6.20 savings.

Artist 52 [7]3 years ago
5 0

Answer: $6.20

Step-by-step explanation:

20% x 31 = 6.2

$6.20 is the tip.

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Which relationship of angle a is correct? A. Cos(a) = 3/5 B. Cos(a) = 4/3 C. Sin(a) = 3/5 D. Sin(a) = 4/3
kotegsom [21]
The correct answer is C.
Sin(a) = 3/5.

Use the law of similarity the big and small triangles, and then use the definition of sinus of the ankle.
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3 years ago
BRAINLIEST! FAST ! PLEASE BE SURE
vaieri [72.5K]

Answer:

-7

Step-by-step explanation:

(1/2)2−6(2−2/3)

1- 6(4/3)

1- (24/3)

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7 0
3 years ago
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Gennadij [26K]
Multiply each by the same constant and you'll get another ratio ie. 5/7 --> 10/14 --> 15/21
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4 years ago
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1. Trapezoid KLMN has vertices K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2) .
chubhunter [2.5K]

Answer:


Step-by-step explanation:

(A) The vertices of the trapezoid KLMN are K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2)

Now, KL= \sqrt{(3-1)^{2}+(1-3)^{2}}=\sqrt{8}[/tex]

LM=\sqrt{(3-3)^{2}+(0-1)^{2}}=1

MN=\sqrt{(1-3)^{2}+(-2-0)^{2}}=\sqrt{8}

NK=\sqrt{(1-1)^{2}+(-2-3)^{2}}=5

Now, as KL and MN  are equal, therefore, KLMN is an isosceles trapezoid.

(B) Since  m∠XWY=47°, therefore ∠XWZ=47+47=94° and ∠ZYW=18°, therefore ∠XYZ=36°( as diagonals bisect the angles)

In ΔXWO,

∠XWO+∠WXO+∠WOX=180°(Angle sum property)

∠WXO=43°

Also, from ΔXOY,

∠OXY=72° using the angle sum property.

Therefore, ∠WXY=43+72=115°

Now, sum of all the angles of a quadrilateral is equal to 360°, therefore

∠WXY+∠XYZ+∠YZW+∠ZWX=360°

115°+36°+∠YZW+94°=360°

∠YZW=115°

Therefore,∠WZY=115°

(C) Since, AB and CD are the two parallel lines as the slope of both the sides are equal.

LetM be the mid point of AB, therefore M=(\frac{-2+4}{2}, \frac{4+3}{2})

=(1,\frac{7}{2})

Also, let N be the mid point of DC, therefore,

N=(\frac{4-2}{2},\frac{-2-5}{2})

=(1,\frac{-7}{2})

Now, length of the mid segment MN= \sqrt{(1-1)^{2}+(\frac{7}{2}+\frac{7}{2})^{2}}=\sqrt{0+49}=7 cm

(D)Given: Kite PQRS,  TS=6cm and TP=8cm

Then, From triangle TSP, we have

(SP)^{2}=(TS)^{2}+(TP)^{2}

(SP)^{2}=36+64

SP=10cm

8 0
3 years ago
Mean, median, and mode. easy! 19 points!
o-na [289]
The answer is the range. The outliner is anything that “lies outside.” Range is the highest#-lowest#. So 78-28 = 50, which is not close the numbers that occurred most often (in this case, the #s in the 30s).
3 0
3 years ago
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