Ask question

Ask question

All categories

3 years ago

14

Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1

cm.
Calculate the density of the sugar in g/cm3

1 answer:

garik1379 [7]3 years ago

7 0

Answer:

$d=1.28\times 10^{-6}\ g/cm^3$

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

$d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3$

So, the density of the bag is $1.28\times 10^{-6}\ g/cm^3$ .

You might be interested in

(4×5)x+ 3x + 2<br>Answer here

Korvikt [17]

Answer:

23x+2

Step-by-step explanation:

4*5=20

20*x=20

3x+20x=23x

23x+2

7 0

3 years ago

If a= 2ft and c= 11ft. Find the missing side of the right triangle

dlinn [17]

Answer:

$\sqrt{117}$ or $3\sqrt{13}$

Step-by-step explanation:

The formula for finding the any side of the triangle is

$a^{2}+b^{2} =c^{2}$

We know that a=2 and c=11, so we can go ahead and plug those into the formula.

$2^{2}+b^{2} =11^{2}$

$4+b^{2} =121$

To find side b, we have to make it alone on one side. Subtract 4 on both side.

$b^{2} =117$

Now square root both sides, and that leaves us with:

$b=\sqrt{117}$ or $3\sqrt{13}$

6 0

3 years ago

How to solve this? Is the question correct? ty :)

bezimeni [28]

Answer:

The proposition is true.

Step-by-step explanation:

Now we proceed to demostrate that expression given is true by algebraic means:

1) $\frac{x^{-1}+y^{-1}}{x^{-1}}+\frac{x^{-1}-y^{-1} }{y^{-1}}$ Given

2) $\frac{y^{-1}\cdot (x^{-1}+y^{-1})+x^{-1}\cdot (x^{-1}-y^{-1})}{x^{-1}\cdot y^{-1}}$ $\frac{a}{b} + \frac{c}{d} = \frac{a\cdot d+b\cdot c}{b\cdot d}$

3) $\frac{x^{-1}\cdot y^{-1}+y^{-2}+x^{-2}-x^{-1}\cdot y^{-1}}{x^{-1}\cdot y^{-1}}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

4) $\frac{x^{-2}+y^{-2}}{(x\cdot y)^{-1}}$ Commutative, associative and modulative properties/Existence of additive inverse/ $a^{b}\cdot c^{b} = (a\cdot c)^{b}$

5) $[(x\cdot y)^{-1}]^{-1}\cdot (x^{-2}+y^{-2})$ Commutative property/Definition of division

6) $(x\cdot y)\cdot (x^{-2}+y^{-2})$ $(x^{-1})^{-1}$

7) $x^{-1}\cdot y + x\cdot y^{-1}$ Distributive property/Associative property/ $a^{b}\cdot a^{c} = a^{b+c}$

8) $(x^{-1}\cdot y^{-1})\cdot y^{2} + (x^{-1}\cdot y^{-1})\cdot x^{2}$ Modulative property/Existence of additive inverse/ $a^{b}\cdot a^{c} = a^{b+c}$

9) $(x^{-1}\cdot y^{-1})\cdot (x^{2}+y^{2})$ Distributive property

10) $(x\cdot y)^{-1}\cdot (x^{2}+y^{2})$ $a^{b}\cdot c^{b} = (a\cdot c)^{b}$

11) $\frac{x^{2}+y^{2}}{x\cdot y}$ Commutative property/Definition of division/Result

4 0

3 years ago

I’ll give Brainly! :) Which equation has the greatest value when solved?

Katena32 [7]

Answer:

I'm pretty sure it's a

Step-by-step explanation:

A:41

B:27

C:38

D:40

6 0

3 years ago

Read 2 more answers

Solve these system of linear equations:

frutty [35]

1.solve for y
2x+4y=12
<u> </u><span><u> -2x -2x</u>
</span><u>4y</u>=<u>12-2x</u>
<u>4 4</u>
y=3-1/2x

step2 plug in y and solve for x
2x+8y=24
2x+8(3-1/2x)= 24
2x+24-4x=24
<u>-2x</u>=<u>0
</u><u>-2 -2</u>
x=0
last step plug in x and solve for y

y=3-1/2x(0)
y=3

5 0

3 years ago