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creativ13 [48]
4 years ago
13

Shi et al. (2013) measured the diffusivity of fluorescein (MW = 332), a fluorescent tracer, in the porcine temporomandibular joi

nt (TMJ) disk using a technique known as fluorescence recovery after photobleaching (FRAP). The TMJ disk consists mostly of water and a large amount of type I collagen. The overall average diffusivity of fluorescein in the TMJ disk was found to be 57.0 μm2 s−1. Using the Brinkman model, estimate the value of κ for fluorescein diffusion in the porcine TMJ disk.
Engineering
1 answer:
Sveta_85 [38]4 years ago
3 0

Answer:

The accuracy of survey radiographs in the diagnosis of acute thoracolumbar disc disease in 36 Dachshunds was determined by comparison with lumbar myelographic findings using iohexol. The value of making radiographs immediately after injection of contrast medium and the effectiveness of oblique radiographs in determining the exact circumferential distribution of extruding or protruding disc material were assessed. The presence of a double contrast medium column, resistance to injection and the presence of cerebrospinal fluid flow during needle placement was also evaluated. The location of the affected disc was accurately determined on survey radiographs in only 26 dogs. The myelographic technique used in this study resulted in the correct intervertebral space being identified, together with the exact circumferential distribution of disc material, in 35 dogs. Survey radiographs alone are inadequate for localization of protruding or extruding disc material

Explanation:

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Fill in the truth table for output A. <br>A = (x+y)(x'+z')(x'+z')​
Novay_Z [31]

Answer:

1+1×1 multiplay then you get the answer

5 0
3 years ago
The disk of radius 0.4 m is originally rotating at ωo=4 rad/sec. If it is subjected to a constant angular acceleration of α=5 ra
Lina20 [59]

Answer:32.4m/s^2

Explanation:

Given data

radius\left ( r\right )=0.4m

Intial angular velocity\left ( \omega_0\right )=4rad/s

angular acceleration\left ( \alpha\right )=5rad/s^2

angular velocity after 1 sec

\omega=\omega_0+\alpha\times\t

\omega=4+5\left ( 1\right )

\omega=9rad/s

Velocity of point on the outer surface of disc\left ( v\right )=\omega_0\timesr

v=9\times0.4 m/s=3.6m/s

Normal component of acceleration\left ( a_c\right )=\frac{v^2}{r}

a_c=\frac{3.6\times3.6}{0.4}=32.4m/s^2

3 0
4 years ago
A helicopter moves horizontally in the x direction at a speed of 120 mi/h. Knowing that the main blades rotate clockwise when vi
devlian [24]

Answer:

The instantaneous axis of rotation=

x = 0 ; z = 8.4 ft

Explanation:

Given:

Speed of helicopter, Vo= 120 mi/h, converting to ft/sec, we have:

\frac{5280 * 120}{60*60}

= 176 ft/s

Angular velociyy, w = 220 rpm, converting to rad/sec, we have: \frac{200*2*pi}{60} =20.95 rad/s

The helicopter moves horizontally in the x direction at a speed of 120 mi/h, this means that the helicopter moves in the positive x direction at 120mi/h

To find the instantaneous axis of rotation of the main blades, we have:

Where Vc = 20.95 rad/s

Vo = 176 ft/s

z = \frac{V_0}{V_c} = \frac{176ft/s}{20.95rad/s}

= 8.4 ft

Therefore the axis of rotation=

x = 0 ; z = 8.4 ft

4 0
3 years ago
What is the standard half-cell potential for the oxidation of methane under acidic conditions? The reaction for methane is as fo
Yuri [45]

Answer:

The element that is oxidized is carbon.

Its oxidation state increased. It increased from -4 to +4

Explanation:

Oxidation is a process that involves increase in oxidation number.

The oxidation number of carbon in CH4 is -4

C + (1×4) = 0

C + 4 = 0

C = 0 - 4 = -4

The oxidation number of carbon in CO2 is +4

C + (2×-2) = 0

C - 4 = 0

C = 0+4 = 4

Increase in the oxidation number of carbon from -4 to +4 means carbon is oxidized

4 0
3 years ago
The 240-ft structure is used to provide various support services to launch vehicles prior to liftoff. In a test, a 12-ton weight
alina1380 [7]

Answer:

hello your question lacks the required question attached below is the missing diagram

Forces in GJ = -4.4444 i.e. 4.4444 tons

Forces in IG = 15.382 tons ( T )

Explanation:

Forces in GJ = -4.4444 i.e. 4.4444 tons

Forces in IG = 15.382 tons ( T )

attached below is the detailed solution

3 0
3 years ago
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