Given:
Three numbers in an AP, all positive.
Sum is 21.
Sum of squares is 155.
Common difference is positive.
We do not know what x and y stand for. Will just solve for the three numbers in the AP.
Let m=middle number, then since sum=21, m=21/3=7
Let d=common difference.
Sum of squares
(7-d)^2+7^2+(7+d)^2=155
Expand left-hand side
3*7^2-2d^2=155
d^2=(155-147)/2=4
d=+2 or -2
=+2 (common difference is positive)
Therefore the three numbers of the AP are
{7-2,7,7+2}, or
{5,7,9}
Answer: 9.4
Step-by-step explanation:
if you see on the screenshot if you draw a line between the 2 it mesures 9.4
Answer:
x= 7
Step-by-step explanation:
11x-2 = 75
11(7) - 2
77 - 2 = 75
x= 7
What are the values to choose from?
