Answer:
The answer to your question is (x - 7)² + y² = 81
Step-by-step explanation:
Data
Center = (7, 0)
radius = 9
Process
To find the standard equation of a circle, just substitute the values of the center and the radius.
Standar equation of a circle
(x - h)² + (y - k)² = r²
-Identify the values of h and k
h = 7 k = 0 and r = 9
-Substitution
(x - 7)² + (y - 0)² = 9²
-Simplification
(x - 7)² + y² = 81
Answer:
![Meeting\ Time = 6:03\ pm](https://tex.z-dn.net/?f=Meeting%5C%20Time%20%3D%206%3A03%5C%20pm)
Step-by-step explanation:
Given
![Start\ Time= 5:45pm](https://tex.z-dn.net/?f=Start%5C%20Time%3D%205%3A45pm)
![Lixin = 18\ min/round](https://tex.z-dn.net/?f=Lixin%20%3D%2018%5C%20min%2Fround)
![Khairul = 360\ seconds/round](https://tex.z-dn.net/?f=Khairul%20%3D%20360%5C%20seconds%2Fround)
![Devi = 4minutes/2\ rounds](https://tex.z-dn.net/?f=Devi%20%3D%204minutes%2F2%5C%20rounds)
Required
Determine their next meeting time
First, we need to get their unit rate in minutes per round
![Lixin = 18\ min/round](https://tex.z-dn.net/?f=Lixin%20%3D%2018%5C%20min%2Fround)
![Khairul = 360\ seconds/round](https://tex.z-dn.net/?f=Khairul%20%3D%20360%5C%20seconds%2Fround)
Convert 360 seconds to minutes
![Khairul = \frac{360}{60} min/round](https://tex.z-dn.net/?f=Khairul%20%3D%20%5Cfrac%7B360%7D%7B60%7D%20min%2Fround)
![Khairul = 6 min/round](https://tex.z-dn.net/?f=Khairul%20%3D%206%20min%2Fround)
![Devi = 4minutes/2\ rounds](https://tex.z-dn.net/?f=Devi%20%3D%204minutes%2F2%5C%20rounds)
Divide by 2/2
![Devi = 2mins/round](https://tex.z-dn.net/?f=Devi%20%3D%202mins%2Fround)
So, we have:
![Lixin = 18\ min/round](https://tex.z-dn.net/?f=Lixin%20%3D%2018%5C%20min%2Fround)
![Khairul = 6 min/round](https://tex.z-dn.net/?f=Khairul%20%3D%206%20min%2Fround)
![Devi = 2mins/round](https://tex.z-dn.net/?f=Devi%20%3D%202mins%2Fround)
Next, is to determine the LCM of 18, 6 and 2
![18=2 * 3 * 3](https://tex.z-dn.net/?f=18%3D2%20%2A%203%20%2A%203)
![6 = 2 * 3](https://tex.z-dn.net/?f=6%20%3D%202%20%2A%203)
![3 = 3](https://tex.z-dn.net/?f=3%20%3D%203)
Their LCM is:
![LCM = 2 * 3 * 3](https://tex.z-dn.net/?f=LCM%20%3D%202%20%2A%203%20%2A%203)
![LCM = 18](https://tex.z-dn.net/?f=LCM%20%3D%2018)
This means that they will meet 18 minutes after their initial time of departure.
So:
![Meeting\ Time = 5:45\ pm + 18\ minutes](https://tex.z-dn.net/?f=Meeting%5C%20Time%20%3D%205%3A45%5C%20pm%20%2B%2018%5C%20minutes)
![Meeting\ Time = 6:03\ pm](https://tex.z-dn.net/?f=Meeting%5C%20Time%20%3D%206%3A03%5C%20pm)
3/24
I’m guessing cause you times 3 by 8 to get 24 which is the amount of possibilities
Ok this is a very question that can solved very easily. So we know that there three numbers, and they are consecutive, this means that they are all one bigger than the number before so for example 1,2, and 3 or 20, 21, and 22. These numbers are called consecutive. Now let's just pretend that the answer to this question is the variable "x". Now x is the smallest number in all the three numbers.
Using our knowledge of consecutive numbers we can say that the next to numbers will be one more than the number before so:
(x+1) and (x+2)
So we have our three numbers: x , x+1 , and x+2. Now let's set these numbers equal to 177.
177 = x + x + 1 + x + 2 → Combine like terms.
177 = 3x + 3 → Subtract 3 from both sides.
174 = 3x → Divide both sides by 3
58 = x
So that means that our first and smallest number is going to be 58 our second number will be +1 so 59 and our third number will be +2 so 60.
So the three numbers will be 58, 59, and 60.
Hope this helped.
9514 1404 393
Answer:
DE = 86
EF = 84
Step-by-step explanation:
We assume that point E lies on segment DF, so that ...
DE + EF = DF
(3x +20) +(2x +40) = 170
5x = 110 . . . . . . . . . . . . . . . collect terms, subtract 60
x = 22 . . . . . . . . . . . . divide by 5
DE = 3×22 +20 = 66 +20 = 86
EF = 2×22 +40 = 44 +40 = 84