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3 years ago

12

Can You use feet to find Surface area

1 answer:

Valentin [98]3 years ago

4 0

Answer:

No

Step-by-step explanation:

Feet is a measurement of length.

Surface area requires a measurement of area.

You can use square feet to measure surface area.

If you multiply two values in the foot unit together, you have square feet.

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Student A, lives in Phoenix, Arizona and submits an assignment for math class. The teacher notices the student IP address is 75.

pentagon [3]

Answer:

Yes, this student copied directly from an online site.

Step-by-step explanation:

According to whatismyip.live, this IP address is from Chandler, Arizona not Phoenix.

7 0

3 years ago

$1.79, $1.61, $1.96, $2.09, $1.84, $1.75 <br> <br> What is the range of gasoline prices?

german

Answer:

0.48

Step-by-step explanation:

The range of a data set is the largest quantity subtracted by the smallest quantity. In this case 1.61 is the smallest. 2.09 is the largest. So we need to do 2.09-1.61 and get the range of 0.48! Stay safe!

4 0

3 years ago

Read 2 more answers

PLZZ help need it bad

AfilCa [17]

Not sure lol i can’t press the link:/

3 0

3 years ago

Solve the following differential equation: y" + y' = 8x^2

PtichkaEL [24]

Answer:

$y=y_p+y_h = \frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$

Step-by-step explanation:

Let's find a particular solution. We need a function of the form $y= ax^3+bx^2+cx+d$ such that

$y'= 3ax^2+2bx+c$ and

$y''= 6ax+2b$

$y'+y''= 3ax^2+2bx+c+6ax+2b = 3ax^2+x(2b+6a)+(c+2b) = 8x^2$

then, 3a= 8, 2b+6a =0 and c+2b = 0. With the first equation we obtain

a = 8/3 and replacing in the second equation 2b+6(8/3) = 2b + 16 = 0. Then, b = -8. Finally, c = -2(-8) = 16.

So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

Now, let's find the solution $y_p$ of the homogeneus equation $y''+y'=0$ with the method of constants coefficients. Let $y=e^{\lambda x}$

$y'=\lambda e^{\lambda x}$

$y''=\lambda^2e^{\lambda x}$

then $\lambda e^{\lambda x}+\lambda^2 e^{\lambda x} = 0$

$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

So, $y_h = C_1 + C_2e^{-x}$ and the solution is

$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

5 0

3 years ago

A middle school with 375 students has 125 students in the eighth grade. Irene says that the eighth-grade class makes up of the s

koban [17]

Answer:

Step-by-step explanation:

8 0

3 years ago