Answer:
The mass of the precipitate that AgCl is 3.5803 g.
Explanation:
a) To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute (NaCl) = 1.46 g
Molar mass of sulfuric acid = 58.5 g/mol
Volume of solution = 
Putting values in above equation, we get:
0.09982 M is the concentration of the sodium chloride solution.
b) 
Moles of NaCl = 
according to reaction 1 mol of NaCl gives 1 mol of AgCl.
Then 0.02495 moles of NaCl will give:
of AgCl
Mass of 0.02495 moles of AgCl:
The mass of the precipitate that AgCl is 3.5803 g.
which means that the volume increased by 26.4 mL in order to compensate for the decrease in pressure.
Like I said, depends on what your initial volume was, but that's how you think of it.
Hope this helped!
An Arrhenius acid by definition dissociates in water to form H3O+ (or H+) ions while an arrhenius base dissociates in water to form OH- ions.
NH4+(aq) can be categorised as an arrhenius acid since it releases H3O+ ions in aqueous media
NH4+(aq) + H2O (aq) ↔ NH3 (aq) + H3O+(aq)
Answer:
did it give you answers to in blanks
Answer: 50 nm
Explanation: Two steps:
1. Divide 3.25/6.5 = 0.5
2. Divide 10^8/10^6 = 10^2
nm^2/nm = nm
Combine: 0.5x10^2 nm
or 50 nm
