While the normal gas flame can
only produce a “operating” to “light blue” type of flame, the Bunsen burner can
at least yield three types of flame. Consequently, the following: <span><span />
Operating flame
– which is yellow/orange in color, near 300° C. </span>
<span><span>·
</span>
Blue flame –
can be imperceptible under normal lighting conditions, near 500° C. The typically
used laboratory type of flame.</span>
<span><span>·
</span>Roaring-blue
flame – forms a triangular shaped in the center of the flame normally light
blue in color and interestingly, it’s a sound-producing flame. Heat is near to
700° C. </span>
Imagine with this three kinds
of flame produced and a Bunsen burner creates compared to a simple normal gas
flame. In sense, the roaring-blue flame proves evident as to why Bunsen burner
is hotter hence, the amount of heat it makes (700°C) it makes.
Answer: TWO WITH LIGHT PINK PRECIPITATE IS
BaCI2 and AI2(SO4)3 AND BaCI2 and NaOH
Ferric hydroxide and aluminium hydroxide are the precipitate u can form by any major reaction.
Explanation: Chemical Reaction: BaCl2 and AgNO3
Ba+2= Barium= Metal
Cl-1= Chlorine = Non-metal
Ag+1 = Silver= Transition Metal
NO3 - = Nitrate= Polyatomic Ion
BaCl2 = Barium chloride
Ag(NO3) = Silver (I) Nitrate
fourth period
The third period is similar to the second, except the 3s and 3p sublevels are being filled. Because the 3d sublevel does not fill until after the 4s sublevel, the fourth period contains 18 elements, due to the 10 additional electrons that can be accommodated by the 3d orbitals.
Answer:
c. 2 OH⁻(aq) + 2 H⁺(aq) ⇒ 2 H₂O(l)
Explanation:
Step 1: Write the molecular equation
The molecular equation includes all the molecular species.
H₂A(aq) + 2 NaOH(aq) ⇒ Na₂A(aq) + 2 H₂O(l)
Step 2: Write the complete ionic equation
The complete ionic equation includes all the ions and the molecular species.
2 H⁺(aq) + A²⁻(aq) + 2 Na⁺(aq) + 2 OH⁻(aq) ⇒ 2 Na⁺(aq) + A²⁻(aq) + 2 H₂O(l)
Step 3: Write the net ionic equation
The net ionic equation includes only the ions that participate in the reaction and the molecular species.
2 OH⁻(aq) + 2 H⁺(aq) ⇒ 2 H₂O(l)
Answer:
The new molarity is 0.614 M
Explanation:
Formula for dilutions is:
M concentrated . Volume of conc = Volume of dil . M diluted
6.54 M . 249 mL = 416 mL . M diluted
Notice that volume of diluted is = Initial volume + What we added of water
(249mL + 167 mL)
(6.54 M . 249 mL) / 416mL = M diluted → 0.614 M
