Answer:
The cyanidin indicator turns blue within a pH range of 5 - 7. The pH of the solution could be 5, 6 or 7.
An indicator is used to determine the endpoint of a titration.
Explanation:
Cyanidin indicator changes colour with each change in pH. In acidic solutions (pH < 7) cyanidin indicator will turn red, through to purple and blue, while in basic solutions (pH > 7), cyanidin indicator will change colour from aquamarine through to green and yellow. The cyanidin indicator turns blue within a pH range of 5 - 7.
Titration is a technique used in analytical chemistry to determine the unknown concentration of a solution. A solution of known concentration is added from a burette to the solution of unknown concentration until the reaction between the two solutions is complete. This known as the endpoint of the experiment. The endpoint of a titration is determined using an indicator which is added to reaction mixture. A colour charge is produced by the indicator at the endpoint of the reaction.
Note: An indicator is a dye of weak organic acids or bases which changes colour with changes in the pH of a solution. Some common indicators are methyl orange, methyl red, phenolphthalein, etc. These indicators are used to monitor the changes in the pH of solutions during a reaction.
Answer:
Variation within genes leads to different genotypes , which can be seen by the individuals having different phenotypes . For example, the dogs above all have different fur colours and fur lengths. Genetic and environmental variation combine together to produce these different phenotypes.
Answer:
The number of D₂O molecules in 300.0 mL of water are 1,003x10²¹
Explanation:
First, you need to know in 300 mL of water how many moles of hydrogen and deuterium are. Then, you must use Avogadro's number to obtain the number of molecules.
In 300 mL of water you have:
=
16,65 moles of H₂O and D₂O
As the 0,01 percent of these moles are D₂O:
16,65 mol × 0,01% = <em>1,665x10⁻³ mol of D₂O</em>
That in number of molecules are:
=
<em>1,003x10²¹ molecules of D₂O</em>
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I hope it helps!