For the excited state of Ca at the absorption of 422.7 nm light,the energy difference is mathematically given as
E= 4.70x10-22 kJ/mol
<h3>What is the energy difference (kJ/mole) between the ground and the first excited state?</h3>
Generally, the equation for the Energy is mathematically given as
E = nhc / λ
Where
h= plank's constant
h= 6.625x 10-34 Js
c = speed of light
c= 3x 108 m/s
Therefore
E = 1*(6.625x 10-34 Js)( 3x 10^8 m/s) / ( 422.7x10^-9)
E= 4.70x10-22 kJ/mol
In conclusion, Energy
E= 4.70x10-22 kJ/mol
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brainly.com/question/13439286
Answer:
0.3936 J/gC
Explanation:
using the formula: q=mcΔt
q= 7032J
m=812g
ΔT = 22C
plug in and solve:
7032=(812)(c)(22)
c=7032/(812)(22)
c=0.39 J/gC
Answer:
Here is the meaning of covalent bond: covalent bond: a chemical bond in which two atoms share some of their valence electrons which creates a force that holds the atoms together
Hope this helps
Sky
250miles is distance
5hours is time
Speed = distance/time
Speed = 250/5
Speed =50miles per hour
50mph
Hope that helps :)
Answer:
- final temperature (T2) = 748.66 K
- ΔU = w = 5620.26 J
- ΔH = 9367.047 J
- q = 0
Explanation:
ideal gas:
reversible adiabatic compression:
∴ q = 0
∴ w = - PδV
⇒ δU = δw
⇒ CvδT = - PδV
ideal gas:
⇒ PδV + VδP = RδT
⇒ PδV = RδT - VδP = - CvδT
⇒ RδT - RTn/PδP = - CvδT
⇒ (R + Cv,m)∫δT/T = R∫δP/P
⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303
∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5
⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212
⇒ T2/T1 = 2.512
∴ T1 = 298 K
⇒ T2 = (298 K)×(2.512)
⇒ T2 = 748.66 K
⇒ ΔU = Cv,mΔT
⇒ ΔU = (3/2)R(748.66 - 298)
∴ R = 8.314 J/K.mol
⇒ ΔU = 5620.26 J
⇒ w = 5620.26 J
⇒ ΔH = ΔU + nRΔT
⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)
⇒ ΔH = 5620.26 J + 3746.787 J
⇒ ΔH = 9367.047 J