No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be

or

so
if w^2-9w+81 is perfect square, factored form is either

or

aka

or
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
4 because it is the only number on the x side of the table that you can get a single value for y from
Answer:
whooops no one had answered u from 50 min!
Answer:
y = (x-3)^2 - 17
Step-by-step explanation:
To complete the square, take the middle term bx and divide it in two. Then take the square.
x^2 - 6x - 8 has bx = -6x. Take -6/2 = -3. Square -3^2 = 9.
Now to finish completing the square add 9 and subtract 9 from one side.
y = x^2 - 6x - 8
y = (x^2 - 6x +9) -9 - 8
y = (x-3)^2 - 17
Answer:
yes
Step-by-step explanation: