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masya89 [10]
3 years ago
6

At a football game Jasmine bought a soft pretzel for $2.25 in a bottle of water for $1.50 she paid with a $5 bill how much thing

s should Jasmine get back
Mathematics
1 answer:
andrew11 [14]3 years ago
3 0

Answer:

$1.25.

Step-by-step explanation:    

We have been given that at a football game Jasmine bought a soft pretzel for $2.25 in a bottle of water for $1.50 she paid with a $5 bill.

First of all let us find how much Jasmine spent on soft pretzel and water bottle by adding the cost of both items.

\text{Total amount spent on both items}=2.25+1.50

\text{Total amount spent on both items}=3.75

To find the amount that Jasmine will get as a change we will subtract the amount spent on both items from 5.

\text{Amount of change that Jasmine will get}=5-3.75

\text{Amount of change that Jasmine will get}=1.25

Therefore, Jasmine will get $1.25 back as change.

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Find the distance between the pair of points and then round your answer to the nearest tenth.
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Answer:

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Step-by-step explanation:

Given the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, distance between (-4, 5) and (4, 0) is calculated as follows:

Let (-4, 5) = (x_1, y_1)

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d = \sqrt{89}

d = 9.4 units (nearest tenth)

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Hope it helps!

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The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000

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Shape approximately normal

Mean 350000

Standard deviation s = \frac{160000}{\sqrt{40}} = 25298

The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.

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