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Citrus2011 [14]
3 years ago
6

When she drives to work, Samantha travels 10 miles in about 15 minutes. Matt travels 23 miles in about 30 minutes. Who has the f

aster average speed? Give their speed in your answer.
Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

At 0.77 mi/min, Matt travels faster than Jennifer, who averages

only 0.67 mi/min.

Step-by-step explanation:

Average speed = distance/time

<em>For Samantha, </em>

Average speed = 10/15

Average speed = 0.67 mi/min

<em>For Matt, </em>

Average speed = 23/30

Average speed = 0.77 mi/min

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Hope this helps :)
3 0
4 years ago
If
Nitella [24]

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

6 0
2 years ago
Ben works part time in a warehouse . His boss is going to send one employee home early . Of his 56 employees 21 are part time .
qaws [65]
21/56 which reduces to 3/8 ...or if u need a percent, it is 37.5%
7 0
3 years ago
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Korolek [52]

Answer:

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Step-by-step explanation:

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Answer:

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The expression is not factorable with rational numbers

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