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Mars2501 [29]
3 years ago
9

Arrange these numbers from least to greatest 2/5 5/7 4/9

Mathematics
2 answers:
BartSMP [9]3 years ago
6 0
The answer is 2/5 4/9 5/7

mr Goodwill [35]3 years ago
4 0
4/9 2/5 5/7 is sorted from least to greatest

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What is the product written in scientific notation?
wel
Answer is C. Definitely not d right off the bat because both exponents are negative so cross that out. After that its just counting zeros.
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3 years ago
Read 2 more answers
1 Solve the compound inequality 4x&gt;-16 or 6x &lt;-48<br>​
Yuliya22 [10]

Answer:

Step-by-step explanation:

4x > -16 reduces to x > -4:  All numbers greater than x = -4 (shaded area to the right of -4).

6x < -48 reduces to x < -8:  All numbers to the left of -8 (shaded area to the left of -8).

Solution:  (-infinity, -4) ∪ (-8, infinity)

The number line between -8 and -4 is not part of the solution set (is not shaded or darkened)

Draw an open circle at -8 and extend an arrow to the left of this circle.  Then draw an open circle at -4 and extend an arrow to the right of this circle.

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3 years ago
Simplify<br> 6^7 /6^5<br> leaving your answer in index form.
Agata [3.3K]

Answer:

36

Step-by-step explanation:

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3 years ago
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jeyben [28]
10/15 =6/9

6*15=90
90/9=10, this is how I found 10,
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7 0
3 years ago
In New York City at the spring equinox there are 12 hours 8 minutes of daylight. The
slamgirl [31]

Answer:

  independent: day number; dependent: hours of daylight

  d(t) = 12.133 +2.883sin(2π(t-80)/365.25)

  1.79 fewer hours on Feb 10

Step-by-step explanation:

a) The independent variable is the day number of the year (t), and the dependent variable is daylight hours (d).

__

b) The average value of the sinusoidal function for daylight hours is given as 12 hours, 8 minutes, about 12.133 hours. The amplitude of the function is given as 2 hours 53 minutes, about 2.883 hours. Without too much error, we can assume the year length is 365.25 days, so that is the period of the function,

March 21 is day 80 of the year, so that will be the horizontal offset of the function. Putting these values into the form ...

  d(t) = (average value) +(amplitude)sin(2π/(period)·(t -offset days))

  d(t) = 12.133 +2.883sin(2π(t-80)/365.25)

__

c) d(41) = 10.34, so February 10 will have ...

  12.13 -10.34 = 1.79

hours less daylight.

5 0
3 years ago
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