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poizon [28]
3 years ago
5

Most adults would erase all of their personal information online if they could. A software firm survey of 601 randomly selected

adults showed that 63% of them would erase all of their personal information online if they could. Complete parts (a) and (b) below. a. Express the original claim in symbolic form. Let the parameter represent the adults that would erase their personal information.b. Find the value of the test statistic.
Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

H_{0}: p=0.5

H_{a}: p>0.5

Test statistic of the sample proportion is ≈ 5.39

Step-by-step explanation:

Let the parameter p represent the proportion of adults that would erase their personal information

H_{0}: p=0.5

H_{a}: p>0.5

Test statistic of the sample proportion can be found as

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of people would erase all of their personal information online if they could (63% or 0.63)
  • p is the proportion assumed under null hypothesis. (0.5)
  • N is the sample size (601)

Then z=\frac{0.61-0.5}{\sqrt{\frac{0.5*0.5}{601} } } ≈ 5.39

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Answer:

Mizuki is here to help! The answer is D!

Step-by-step explanation:

Ok... So there are 24 students in the class and no other students in the class has the same name right? So the fraction should be \frac{3}{24} since there are three madisons, which will be 0.125!

Since three people have the same name, everyone else gets less probability of getting called so the answer would be D.

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Delicious77 [7]

The probability that a player will be asked a math question and then a music question is 0.03125

<h3>How to determine the probability?</h3>

The size of the sections are given as:

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Hi there, 
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