Answer:
This is verry easy! Is 105.56,do u need expabation?
1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
0.5×2/2=1/2 is the required fraction.
The answer is C Kay. Got it?
Answer:
Center: (0, 0)
Radius: 4
Step-by-step explanation:
Circle Standard Equation: (x - h)² + (y - k)² = r²
(h, k) is center
r is radius
We see that our <em>h</em> and our <em>k</em> are both 0.
∴ Our center is (0, 0), origin.
We see that our r² = 16
√r² = √16
∴ Our radius is equal to 4
