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kati45 [8]
2 years ago
9

*ANSWER IMMINENTLY GIVING 20 POINT BRAINIEST*

Mathematics
2 answers:
grigory [225]2 years ago
8 0

Answer:

Its not 20 points lol

Step-by-step explanation:

let me know when its 20 and i will answer

Rus_ich [418]2 years ago
4 0
4.3x - 12
=1/10 x(43x-120)
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Math problem need help
MrRa [10]
Dang girl that’s really hard hope u get it
8 0
2 years ago
A car travels at 60 miles per hour. If d is the distance traveled and t is the time in hours:
erastovalidia [21]

Answer:

Step-by-step explanation:

first we will break the parts of the question down:

d= distance

t= time

function: d=t(60)

the <em>independent </em>variable is t, time, because the (distance) that the car travels <u>depends  </u> on how long the car has been traveling for (time) meaning that the dependent value is distance.

A table we can create with 5 coordinate pairs is:

(time)        (distance)

1 hr            60miles

2 hr           120 miles

3 hr          180 miles

4 hr            240 miles

5 hr           300 miles

(to graph the coordinate pairs, you can graph the points listed in the table. the time value represents the x value since it is the independent variable, and the y value will be the distance values since it is dependent.)

<u />

8 0
3 years ago
Count one of four equal parts
Sedbober [7]

Answer:

i think this is it 1/4 but need more context

Hope this helps :)

Step-by-step explanation:

5 0
2 years ago
4(3+2x) + 2 = 46 , solve for x I need help I'm a bit confused
Reil [10]

Answer:

x=4

Step-by-step explanation:

4(3+2x)+2=46

12+8x+2=46

12+8x=44

8x=32

x=4

8 0
3 years ago
Read 2 more answers
The figure below shows a straight line AB intersected by another straight line t:
BaLLatris [955]

When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.

If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.

Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so

m\angle 1+m\angle 2=180^{\circ}.

Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so

m\angle 3+m\angle 2=180^{\circ}.

Subtract from the first equation the second equation:

m\angle 1+m\angle 2-(m\angle 3+m\angle 2)=180^{\circ}-180^{\circ},\\ m\angle 1-m\angle 3=0,\\ m\angle 1=m\angle 3.

Similarly you can prove that m\angle 2=m\angle 4.

4 0
3 years ago
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