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AysviL [449]
3 years ago
9

Choose the equation for the graph

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer: a) Y= 2|x-3|+1

Step-by-step explanation:

Hope this helps

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A math class has a total of 31 students. The number of females is seven less than the number of meals. How many miles and how ma
Nadusha1986 [10]

Answer:

Male-19&Female-13

Step-by-step explanation:

See the image for solution

Hope it helps

Have a great day

3 0
2 years ago
In Store A the price of mayonnaise went
vazorg [7]
It’s 3 because you take the sum of all decreases (which is $9) and divide them by 3
7 0
3 years ago
How do you do number 15 and 17? Help please?
vodomira [7]
15)

m = Miguel Indurian titles amount        l = Lance Armstrong titles amount

they both won titles to the tour de france, if we add all together, they sum up to 12 for both of them
so.. whatever "m" and "l" are, we could say that m + l = 12

now... Miguel won 2 fewer than Lance, so, whatever "l" is, m = l - 2
thus    \bf \begin{cases}
\boxed{m}=l-2\\\\
m+l=12\\
----------\\
\left( \boxed{l-2} \right)+l=12
\end{cases}

solve for "l", to see how many Lance won

how many did Miguel win? well,  m = l - 2

---------------------------------------------------------------------------------

17)

c = mgs amount in 12oz cup of regular coffee at starbucks
d = mgs amount in 12oz cup of regular decaffeinated coffee at starbucks

we know the regular coffee cup, has 13 times more than the decaf, same 12ouncer

thus whatever "c" and "d" are, we know that c = 13d
both 12ouncers put together, yield 280mgs of caffeine

so, one could say that whatever "c" and "d" are, c + d = 280

thus      \bf \begin{cases}
\boxed{c}=13d\\\\
c+d=280\\
----------\\
\left(  \boxed{13d}\right)+d=280
\end{cases}

solve for "d" to see how much is in the decaffed cup

the regular coffee cup?  well c = 13d
8 0
3 years ago
What statement is true about f(x)=2x
inna [77]

Answer:

Subtract

2

x

from both sides of the equation.

f

(

x

)

−

2

x

=

0

Step-by-step explanation:

5 0
3 years ago
Please dont ignore, Need help!!! Use the law of sines/cosines to find..
Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

<h3>16</h3>

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

  • \sin{A} = \sin{103\textdegree{}},
  • The opposite side of angle A a = BC = 26,
  • The angle C is to be found, and
  • The length of the side opposite to angle C c = AB = 6.

\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}.

\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}.

\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}.

Note that the inverse sine function here \sin^{-1}() is also known as arcsin.

<h3>17</h3>

By the law of cosine,

c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C},

where

  • a, b, and c are the lengths of sides of triangle ABC, and
  • \cos{C} is the cosine of angle C.

For triangle ABC:

  • b = 21,
  • c = 30,
  • The length of a (segment BC) is to be found, and
  • The cosine of angle A is \cos{123\textdegree}.

Therefore, replace C in the equation with A, and the law of cosine will become:

a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}.

\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}.

<h3>18</h3>

For triangle ABC:

  • a = 14,
  • b = 9,
  • c = 6, and
  • Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}.

\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}.

\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree.

<h3>15</h3>

For triangle DEF:

  • The length of segment DF is to be found,
  • The length of segment EF is 9,
  • The sine of angle E is \sin{64\textdegree}}, and
  • The sine of angle D is \sin{39\textdegree}.

Apply the law of sine:

\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}

\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9.

7 0
3 years ago
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