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sdas [7]
2 years ago
10

A math class has a total of 31 students. The number of females is seven less than the number of meals. How many miles and how ma

ny females are in the class?
Mathematics
1 answer:
Nadusha1986 [10]2 years ago
3 0

Answer:

Male-19&Female-13

Step-by-step explanation:

See the image for solution

Hope it helps

Have a great day

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Any of these??? the whole page? Please it's due in 2 hours and I would love the help!
Vinvika [58]
9.This is because it goes through the whole circle passing through the centre point. at the full width
The rest are pretty easy. I'm sure you can manage. Good luck!
6 0
3 years ago
GEOMETRY- What is the area of the figure, show your work please!
Kamila [148]
Since this is a 45-45-90 right triangle, the hypotenuse = sqrt2 * leg
24 is the hypotenuse so we need to find the leg.
24 = sqrt2 * leg
Divide both sides by sqrt2
leg = 16.97
A = (1/2)b*h
A = (1/2)*16.97*16.97
A = 144ft^2
8 0
3 years ago
A yard is equal in length to 3 feet the function takes a measurement in yards and returns a measurement and see what number will
Alik [6]

Answer:

It will return 31.5 ft

Step-by-step explanation:

Here, the function is as follows;

let the yard be represented as y and the f be the feet

It takes in yards and return feet

Mathematically, using the relation between the two;

So for every yards it takes in, it returns 3 times the value in feet

Thus, for 10.5 yards, what it will return will be;

10.5 * 3 = 31.5 ft

7 0
3 years ago
Which is greater 3 miles or 5,000 yards? How much greater?
Brilliant_brown [7]
5,000 yards is greater
3 0
3 years ago
Read 2 more answers
For each explicitly-defined sequence below, write the first few terms. Then use the terms to write a recursive equation.
julia-pushkina [17]

Answer:

Step-by-step explanation:

Problem A

t(1) = 2(1) + 5

t(2) = 2*2 + 5 = 9

t(3) = 2*3 + 5 = 11

t(4) = 2*4 + 5 = 13

So this is the explicit result. Now try it recursively.

t_3 = t_2 + 2

t_3 = 9 + 2

t_3 = 11          which is just what it should do.

t_n = t_(n - 1) + 2

Problem B

t(1) = 3 * 1/2

t(1) = 3/2

t(2) = 3*(1/2)^2

t(2) = 3 * 1/4

t(2) = 3/4

t(3) = 3*(1/2)^3

t(3) = 3 * 1/8

t(3) = 3/8

t(4) = 3 (1/2)^4

t(4) = 3 (1/16)

t(4) = 3/16

So in general

t_n = t_n-1 * 1/2

For example t(5)

t_5 = t_4 * 1/2

t_5 = 3 /16 * 1/2 = 3/32

6 0
3 years ago
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