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dexar [7]
3 years ago
9

Use the 2 highlighted points to find the equation of a trend line in slope intercept form

Mathematics
2 answers:
ahrayia [7]3 years ago
7 0
Use rise over run to find the answer
Dominik [7]3 years ago
3 0

Answer:

The slope intercept form of trend line is y=200x-399000.

Step-by-step explanation:

The slope intercept form of a line is

y=mx+b

Where, m is slope and b is y-intercept.

The coordinates of highlighted points are (2000,1000) and (2012,3400).

If a line passes through two points then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

The slope of the trend line is

m=\frac{3400-1000}{2012-2000}

m=\frac{2400}{12}=200

The slope of the line is 200.

Point slope form of a line is

y-y_1=m(x-x_1)

The slope of the trend line is 200 and it passes through (2000,1000). So, the equation of trend line is

y-1000=200(x-2000)

y-1000=200x-400000

Add 1000 on both the sides.

y-1000+1000=200x-400000+1000

y=200x-399000

The slope of the line is 200 and y-intercept is -399000.

Therefore the slope intercept form of trend line is y=200x-399000.

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Business/multivariable calc question<br> help needed asap!!!!
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There is a <u>   min   </u>  value of <u>   800   </u> located at (x,y) = <u>   (16, 12)   </u>

==========================================================

Explanation:

Let's solve the second equation for y

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3y = 100-4x

y = (100-4x)/3

We'll plug that into the first equation

f(x,y) = 2x^2+2y^2

g(x) = 2x^2+2((100-4x)/3)^2

g(x) = 2x^2+(2/9)*(100-4x)^2

g(x) = 2x^2+(2/9)*(10,000-800x+16x^2)

This graphs a parabola that opens upward, due to the positive leading coefficient. This g(x) curve has its vertex point at the minimum.

Apply the derivative to help find the minimum

g(x) = 2x^2+(2/9)*(10,000-800x+16x^2)

g ' (x) = 4x+(2/9)*(-800+32x)

------------------------

Set the derivative function equal to 0 and solve for x

g ' (x) = 0

4x+(2/9)*(-800+32x) = 0

4x+(2/9)*(-800)+(2/9)*(32x) = 0

4x-1600/9+(64/9)x = 0

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100x-1600 = 0

100x = 1600

x = 1600/100

x = 16

Use this x value to find y

y = (100-4x)/3

y = (100-4*16)/3

y = (100-64)/3

y = 36/3

y = 12

-----------------------

Therefore, (x,y) = (16,12) leads to the largest value of f(x,y) = 2x^2+2y^2

That smallest f(x,y) value is...

f(x,y) = 2x^2+2y^2

f(16,12) = 2*16^2+2*12^2

f(16,12) = 800

8 0
3 years ago
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