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2 years ago

The product of which expression contains four decimal places?

Mathematics

1 answer:

Naya [18.7K]2 years ago

3 0

Answer:

D.) 14.2*0.784

Step-by-step explanation:when you calculate it, there is 4 numbers behind the decimal point.

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Solve the quadratic by factoring. x^2-5x-31=5

torisob [31]

Answer:

$x = - 4\: or \: x = 9$

Step-by-step explanation:

make one side equal to zero:

${x}^{2} - 5x - 36 = 0$

find two factors that multiply to -36 and add to -5 (-9 & 4)

${x }^{2} - 9x + 4x - 36 = 0$

factorise

$x(x - 9) + 4(x - 9) = 0$

$(x + 4)(x - 9) = 0$

solve for x

$x = - 4 \: or \: x = 9$

5 0

3 years ago

Divide 6 divided by 3/5 Answer only if u know please:)

meriva

Answer:

The answer is 10 or 10/1

3 0

2 years ago

Find the vertices of the following functions. Y=4(x-2)(x-3) Y=-4(x+2)^2 -5

Natalija [7]

1) 5/2 , -1
2) -2,-5

8 0

2 years ago

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

yaroslaw [1]

Answer:

The value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

$4x^2-3x+9=2x+1$

which could also be written as:

$4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0$

The quadratic formula for the quadratic equation of the type:

$ax^2+bx+c=0$ is given as:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}$

Hence, the value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

8 0

2 years ago

Read 2 more answers

Please help solves asap

Anon25 [30]

Answer:

8=41

7=49

10=41

9=49

Step-by-step explanation:

angle 8 is given and since 7 and 8 make 90 then 7 =49 because 90-41=49. 10 and 8 are the same size (at least it looks like it) therefore 7 and 9 are the same too. So that is how I got the answers.

7 0

2 years ago