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4 years ago

Solve for x,y, and z and please explain answer. 4x-3y+2z=-29 6x+2y-z=-16 -8x-y+3z=23

1 answer:

3 0

8x - 6y + 4z = -58
-8x - y + 3z = 23
-7y + 7z = -35
7 (z-y) = -35
z - y = -5
z = y - 5
4x - 3y + 2y - 10 = -29
6x + 2y - y + 5 = -16

4x - y = -19
6x + y = -21

10x = -40

x = -4
y = 3
z = -2

Thank you very much.
(Took me too long...)

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1 year ago

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

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$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
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$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
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\qquad \sqrt{52}\\
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