Question

The perimeter of a rectangle is 64 feet. The length of the rectangle is 3 times the width of the rectangle. If w represents the width of the rectangle, the equation that represents the perimeter is 2 (3 w) + 2 w = 64. Which shows the first step that should be taken to verify that the width of the rectangle is 8? A regular hexagon and a rectangle have the same perimeter, P. A side of the hexagon is 4 less than the length, l, of the rectangle. The width of the rectangle, w, is 2 less than the length of the rectangle. What is the perimeter of the hexagon?

Answer 1

Step-by-step explanation:

given the perimeter is

64ft

the length l= 3w

we know that the perimeter of a rectangle is given as

P=2l+2W

but L=3w

64=2(3w)+2w

64=6w+2w

64=8w

divide both sides by 8 we have

w=64/8

w=8ft

also

let the lenght of the rectangle be l

side of hexagon=l-4

perimeter of hexagon

P=5(l-4)

P=5l-20

width of rectangle w=l-2

perimeter of rectangle= 2l+2w

but w=l-2

5l-20= 2l+2(l-2)

5l-20=2l+2l-4

5l-20=4l-4

5l-4l=-4+20

l=16ft

perimeter of hexagon

P=5(l-4)

put l=16

perimeter of hexagon

P=5(16-4)

p=5(12)

P=60ft