Ask question

Ask question

All categories

3 years ago

14

88 cubic feet per year express pint per day?

1 answer:

beks73 [17]3 years ago

6 0

Answer:

14.4282 or 14.4 rounded

Step-by-step explanation:

You might be interested in

A manufacturer of bolts has a quality-control policy that requires it to destroy any bolts that are more than 4 standard deviat

Doss [256]

Answer:

more than 15.40 cm and less than 14.60 cm

Step-by-step explanation:

A manufacturer of bolts has a quality control policy that requires it destroy any bolts that are more than 4 standard deviations from the mean.

mean length= 15 cm

standard deviation= 0.10 cm

4 standard deviation from mean= 15±(4×0.10)

therefore, bolts of length more than 15+0.4, and less than 15-0.4 will be destroyed

= 15.40 cm and 14.60 cm

4 0

3 years ago

Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo

Shkiper50 [21]

Answer:

a) $P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335$

b) $P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452$

c) $P(X \geq 8) = 1-P(X$

d) $P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that $X \sim Poisson(\lambda=4)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda$

$E(X)=\mu =\lambda=4$ , $Var(X)=\lambda=2$ , $Sd(X)=2$

a. Compute both P(X≤4) and P(X<4).

$P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183$

$P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733$

$P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465$

$P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646$

$P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)$

$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692$

b. Compute P(4≤X≤ 8).

$P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595$

$P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298$

$P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452$

c. Compute P(8≤ X).

$P(X \geq 8) = 1-P(X$

$P(X \geq 8) = 1-P(X$

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

$P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

4 0

3 years ago

A person is going to fly from New York to London. If he leaves at 4:00 p.m., Eastern Standard Time and the flight lasts 4 1/2 ho

Lyrx [107]

If they leave at 4 pm it is 5 hours ahead so it will be 7 pm

7 0

3 years ago

Read 2 more answers

Which of the following numbers is to the left of 5 2/3

yanalaym [24]

Answer:

C

Step-by-step explanation:

When you convert 5 2/3 to the common denominator as C, it is 5 8/12 which is larger than c meaning c is on the left of 5 2/3

5 0

3 years ago

Read 2 more answers

Each person in a group buys a movie ticket, a drink, and a popcorn. How much does the group pay when there are 5 people in the g

Leya [2.2K]

Answer:

10.75$

Step-by-step explanation:

$5.00 + $2.75 + $3.00 = $10.75 x5 = $53.75

Ticket Drink Popcorn Multiply it by five,

Results is $53.75

Make sure to brainiest me!

- Jackson

8 0

2 years ago