A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter
her second litter had 3 more pups than her first.( first litter +3)=2nd litter
Find the number of pups in her litter
Treat this like a slope formula. Y2-y1 divided by x2-x1.
Your y2 value is the second population
Y1= value of first population.
X2= second year they give
X1= first year they give.
4700-3650
_________
2014-2012
1050
____
2
525 is the increase a year
Answer: Our required probability is 0.65.
Step-by-step explanation:
Since we have given that
18-20 Not 18-20 Total
Male 0.23 0.35 0.58
Female 0.16 0.26 0.42
Total 0.39 0.61 1
P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)
P(female or between 18-20) = 0.42+0.39-0.16
P(female or between 18-20) = 0.65
Hence, our required probability is 0.65.
Answer:
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more ponits not fair
Step-by-step explanation:
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