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3 years ago

Fish is $20 a kilogram your recipe asks for 1/2 kilogram. How much will it cost

Mathematics

1 answer:

lora16 [44]3 years ago

5 0

Known :

1 kg = $20

Asked :

½ kg = $...?

Answer :

1 kg = $20

½ kg = ½ × $20

= $10

Hope it helps and is useful :)

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Find the length of ST

Andru [333]

Answer:

$ST = 12$

Step-by-step explanation:

By AA Similarity, triangles ASR and EST are similar.

The ratio of the lengths of the sides of triangle ASR to those of EST is 6/8 or 3/4.

$\dfrac{SR}{ST} = \dfrac{3}{4}$

Also,

$SR + ST = 21$

By a rule of proportions, you get

$\dfrac{SR + ST}{ST} = \dfrac{3 + 4}{4}$

$\dfrac{21}{ST} = \dfrac{7}{4}$

$7ST = 4 \times 21$

$7ST = 84$

$ST = 12$

3 0

3 years ago

What is 9n=1(98-2n) equal to? Id really appreciate if you could answer both though

borishaifa [10]

N=32/3as a fraction alternative form is n=10.6

5 0

2 years ago

SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin

laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

Empirical rule to determine the percent:

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$$Z(X)=\frac{x-\mu}{\sigma}$

$$Z(433)=\frac{433-\ 433}{90}=0$

$$Z(523)=\frac{523-\ 433}{90}=1$

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. $((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%$

Here μ to μ + σ = $\frac{68\%}{2} =34\%$

Hence 34% of the scores lie between 433 and 523.

8 0

3 years ago

The vertex of this parabola is at (2, -4). When the y-value is -3, the x-value is -3. What is the coefficient of the squared ter

lyudmila [28]

Answer:

The squared term is 1/25

Step-by-step explanation:

The parabola equation in the vertex form is

$y = a \times (x - h)^2 + k$

where point (h,k) is the vertex and a is the squared term. In this case h = 2 and k = -4. On the other hand, we know that y = -3 and x = -3 are in the parabola. Replacing these values in the formula gives

$-3 = a \times (-3 - 2)^2 - 4$

Solving for a

$-3 + 4 = a \times (-5)^2$

$1 = a \times 25$

$a = \frac{1}{25}$

6 0

3 years ago

Which of the following is equivalent to sec2θ−1sec2θ for all values of θ for which sec2θ−1sec2θ is defined?

galina1969 [7]

Answer:

$2 sin^2 \theta$

Step-by-step explanation:

According to the scenario, the following information is given:

$= \frac{sec^2 \theta - 1 }{sec^2 \theta}$

$= (\frac{1}{\frac{cos^2\theta}{\frac{1}{cos^2\theta} }} - 1)$

$= 1 - cos^2\theta\\\\= 1 - (1 - 2 sin^2 \theta)\\\\= 2 sin^2 \theta$

Therefore for the given equation, the answer is $2 sin^2 \theta$

5 0

3 years ago