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julsineya [31]
3 years ago
6

Fish is $20 a kilogram your recipe asks for 1/2 kilogram. How much will it cost

Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Known :

1 kg = $20

Asked :

½ kg = $...?

Answer :

1 kg = $20

½ kg = ½ × $20

= <u>$</u><u>1</u><u>0</u>

<em>Hope it helps and is useful</em><em> </em><em>:</em><em>)</em>

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uniforms for a baseball team cost $600 plus $96 for caps. twelve players split the cost equally. which expression shows how much
PilotLPTM [1.2K]
600+96= 696
696÷ 12= 58
so each player pays $58.
4 0
3 years ago
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If n erasers have a weight of 80 grams, what is the total weight of 50 erasers?
Black_prince [1.1K]

Answer:

The\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.

Step-by-step explanation:

As given

if n erasers have a weight of 80 grams .

I.e

n erasera =  80 grams.

1 erasers weight .

1\ erasers\ weight = \frac{80}{n}

Now find out the weight of the 50 erasers.

Weight\ of\ 50\ erasers = \frac{50\times 80}{n}\ grams

Simplify the above

Weight\ of\ 50\ erasers = \frac{4000}{n}\ grams

Therefore\ the\ weight\ of\ the\ 50\ erasers\ be\ \frac{4000}{n}\ grams.

6 0
3 years ago
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Which value is MEAN of the data set?
Fynjy0 [20]

Answer:

D

Step-by-step explanation:

There is no data set so there is no data to find the mean of.

3 0
3 years ago
Which names are other ways to name ∠1?
Drupady [299]
A), e), and g) are the correct answers
4 0
3 years ago
A bivariate data set has x = 21, sx = 13, y = 55, sy = 27, and r = .88. What is the equation for the regression line of y on x?
earnstyle [38]

Answer:

c) y=16.57+1.83x

Step-by-step explanation:

Equation for regression line of y on x is given as

\hat{y}=mx+b --- (1)

where

\hat{y} = predicted value

m = slope of line

b = intercept

m and b are found as

m=r\frac{S_{y}}{S_{x}}---(2)\\\\b=\bar{y}-m\bar{x}---(3)

r = correlation coefficient = 0.88

Sx = standard deviation for independent variable x = 13

Sy = standard deviation for dependent variable y = 27

\bar{x} = mean value of independent variable x = 21

\bar{x} = mean value of dependent variable y = 55

Substituting these values in (2) and (3)

m=r\frac{S_{y}}{S_{x}}\\\\m=(0.88)\frac{27}{13}\\\\m=1.83

b=\bar{y}-m\bar{x}\\\\b=55-(1.827)(21)\\\\b=16.57

Putting these values of m and b in (1)

y=1.83x+16.57

5 0
3 years ago
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