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Rama09 [41]
3 years ago
13

Simplifly3/4(-10+2/5)?​

Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer: 7.2000

The zeros just keep repeating

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What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
Citrus2011 [14]

The easiest way to answer this is to try all choices, plug in values for the 1st term and 2nd term then check if the answer matches with 5 and 2. (n = 1 and n = 2)

We know that n starts with 1 because that is our 1st term, we do not have 0th term, therefore that leaves us with 2 choices.

Choice 1: an = 5 − 2(n − 1); all integers where n ≥ 1

n = 1

a1 = 5 – 2 (1 – 1) = 5 – 2 (0)

a1 = 5

 

n = 2

a2 = 5 – 2 (2 – 1) = 5 – 2 (1)

<span>a2 = 3   (FALSE!)</span>

 

Choice 2: an = 5 − 3(n − 1); all integers where n ≥ 1

n = 1

a1 = 5 – 3 (1 – 1) = 5 – 3 (0)

a1 = 5

 

n = 2

a2 = 5 – 3 (2 – 1) = 5 – 3 (1)

<span>a2 = 2   (TRUE)</span>

 

Therefore the correct answer is:

<span>an = 5 − 3(n − 1); all integers where n ≥ 1</span>

8 0
4 years ago
Read 2 more answers
*HELP*
Harlamova29_29 [7]

Answer:

96 dollars and 50 cents

Step-by-step explanation:

5 0
3 years ago
20 is 40% of what number
tensa zangetsu [6.8K]
Is means equal

of means multiplication

so

20 = 40% x a

40% = 40/100 = 4/10 = 2/5

So

20 = 2/5 x a

Multiply both sides by 5/2

20 x 5/2 = a

10 x 5 = a

a =50

So your final answer is \boxed{\bf{50}}
5 0
3 years ago
Read 2 more answers
Is 1/2*4/5 less than 4/5
kati45 [8]
No hope this helps bc it’s being multiplied and even then u simplify
4 0
3 years ago
Find dy/dx when y = Ln (sinh 2x). A. 2 cosh 2x B. 2 sech 2x C. 2 coth 2x D. 2 csch 2x
givi [52]
The function given is a composite function. Let's work from the outside in:
y=(ln(sinh(2x)))

First step:
\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]

Now, let's work it out:
\frac{dy}{dx} = \frac{1}{sinh(2x) } *   \frac{d}{dx}[sinh(2x)]

Next step:
\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) *  \frac{d}{dx}[2x]

Next step:
\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) *2

Simplify:
\frac{dy}{dx} = \frac{2cosh(2x)}{sinh(2x) }

Simplify further:
\frac{dy}{dx} = 2 (\frac{cosh(2x)}{sinh(2x)})

Remember that:
{\frac{cosh(x)}{sinh(x)} = coth(x)

So, your final answer is:
\boxed{ \frac{dy}{dx} = 2coth(2x) }

So, your answer is C. Hope I could help you!
8 0
4 years ago
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