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2 years ago

How does the 3 in 350 compare to the 3 in 430?

Mathematics

1 answer:

mr Goodwill [35]2 years ago

5 0

The 3 in 350 is in the hundreds place, and the 3 in 430 is in the 10s place.

Hope i helped:D

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Kathryn deposits 100 into an account at the beggining of each 4 year period for 40 years. The account credits interest at an eff

OleMash [197]

Answer:

6194.84

Step-by-step explanation:

Using the formula for calculating accumulated annuity amount

F = P × ([1 + I]^N - 1 )/I

Where P is the payment amount. I is equal to the interest (discount) rate and N number of duration

For 40 years,

X = 100[(1 + i)^40 + (1 + i)^36 + · · ·+ (1 + i)^4]

=[100 × (1+i)^4 × (1 - (1 + i)^40]/1 − (1 + i)^4

For 20 years,

Y = A(20) = 100[(1+i)^20+(1+i)^16+· · ·+(1+i)^4]

Using X = 5Y (5 times the accumulated amount in the account at the ned of 20 years) and using a difference of squares on the left side gives

1 + (1 + i)^20 = 5

so (1 + i)^20 = 4

so (1 + i)^4 = 4^0.2 = 1.319508

Hence X = [100 × (1 + i)^4 × (1 − (1 + i)^40)] / 1 − (1 + i)^4

= [100×1.3195×(1−4^2)] / 1−1.3195

X = 6194.84

4 0

3 years ago

Read 2 more answers

A craft stores sells ribbons in packages of different lengths the price of each package is shown which package offers the lowest

ankoles [38]

Answer:

Package 3 has the lowest unit price.

Step-by-step explanation:

7 0

2 years ago

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What is the Tenth COMMON FACTOR of 6 and 9? (DO NOT respond with the LCM of 6 and 9)

Damm [24]

GMC Answer : 3 because of there

4 0

3 years ago

Please can someone help me with this question

sasho [114]

Answer:

r = - $\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$ = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

( $\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ( $\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by 5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5 to the left of (m ^2) r

6a+r=5m^2)r

Subtract 5m^2)r from both sides of the equation.

6a+r-5m^2)r=0

Subtract 6a from both sides of the equation.

r-5m^2)r=-6a

Factor r out of r-5m^2)r

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!

4 0

3 years ago

X/3=-3 can someone help me

laiz [17]

Answer:

x = - 9

Step-by-step explanation:

Given

$\frac{x}{3}$ = - 3 ( multiply both sides by 3 to clear the fraction )

x = - 9

7 0

3 years ago