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stiv31 [10]
3 years ago
9

About 12% of individuals write with their left hands. If a class of 130 students meets in a classroom with 130 individual desks,

and 14 of the students write with their left hands, the probability that not all left handed students will have access to a special desk, constructed for people who write with their left hands is _______
Mathematics
1 answer:
Lynna [10]3 years ago
3 0

Answer:

0.1019

Step-by-step explanation:

Probability, p=12%=0.12

Sample size, n=130 students

Those writing with left=14 students

Using the formula for binomial distribution

P(X≤x)=\left[\begin{array}{}n\\x\end{array}\right]p^{x}(1-p)^{n-x}

Substituting 0.12 for p, 130 for n, 14 for x we obtain

P(X≤x)=\left[\begin{array}{}130\\14\end{array}\right]0.12^{14}(1-0.12)^{130-14}

P(X≤x)=130C14*0.12^{14}(0.88)^{116}

P(X≤x)=0.1019

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Simplify 14 3/8% ?!!
Flura [38]

Answer:

4 2/3

Step-by-step explanation:

Simplify 14/3 reduces the fraction 14/3 to the lowest form. You can change the numerator or denominator to simplify any other fraction.

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3 years ago
JUST ANSWER PLEASE!!! QUICK
jeka57 [31]

Answer:

<u>Options 1 and 3</u>

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

We will check which system of equation has the same solution.

<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

                 (P+2T)x + (Q+2U)y = R-2V  ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

 (P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

<u>System C)</u> (T-P)x + (U-Q)y = V-R  ⇒(5)

                  Tx + Uy = V  

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

<u>System D)</u> (T-P)x + (Q+U)y = V-R  ⇒(6)

                  Tx + Uy = V  

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) <u>OR </u>(T-P) and (Q-U)

So, system D has not the same solution of (2,9)

<u>System E)</u> (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

                  Tx + Uy = V  

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

<u>Options 1 and 3</u>

5 0
2 years ago
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horrorfan [7]

Answer:

D. 40%

Step-by-step explanation:

15/6=40% AKA 4/10

8 0
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zhenek [66]

Answer:

The leading coefficient is -7

Step-by-step explanation:

The leading coefficient is the number in front of the highest power variable.  In this case, the highest variable is x^2 and in front of it is -7.  Therefore, the leading coefficient is -7

Answer:  The leading coefficient is -7

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AfilCa [17]

Answer:

-3<x<3

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let y=0

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0=(x+3)(x-3)

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