Distance= speed * time
So multiply speed and time to get the value of distance
20*9.8 =196 meters
To solve this problem, we will first apply the concepts related to trigonometric relations and then the conservation of energy. By the trigonometric relations we will find the height for the calculation of the potential energy. For the conservation of energy we will give the relationship between the kinetic energy and initial potential with the final kinetic energy. Therefore, first the height by trigonometric relation we have



Then by conservation of energy


Here,
m = mass
g = Gravitational acceleration
v = Velocity
Rearranging to find the final velocity,



Therefore the correct answer is D.
Answer:
A. <em>Loses PE and gains KE
</em>
Explanation:
Statement is incomplete. Complete statement of problem is:
<em>1. An object from a certain height falls freely. Which of the following happens to PE and KE when the object is half on its way down?
</em>
A. <em>Loses PE and gains KE
</em>
B. <em>Gains PE and loses KE
</em>
C. <em>Loses both PE and KE
</em>
D. <em>Gains both PE and KE</em>
If we neglect the effects of any conservative force, the application of the Principle of Energy Conservation is reduced to a sum of gravitational potential (
) and translational kinetic energies, measured in joules. That is:
(Eq. 1)
Let assume that an object falls from a height
with a speed of zero. By definitions of gravitational potential and translational kinetic energies the previous is expanded. If final height is the half of initial value, then:
(Eq. 1b)


In a nutshell, translational kinetic energy is increased at the expense of diminishing gravitational potential energy. The correct answer is A.
Example? I see none, so I'll make up my own.
An example of kinetic energy, is like bicycle riding down a hill.
Kinetic energy, is basically <em>moving</em> energy.
Hope this helps!!!:)