The equations of motion to use for a constant acceleration a = g = -9.81:
at the highest point the velocity must be zero:
combine both equations:
Solve for v₀:
Answer:
Book of mass 2 kg is lifted from floor to the table. The height between floor and the table is 1.5 m. Calculate the work done by gravitational force.
Answer:
ΔL = L0 C ΔT
We need to find C the constant of expansivity
C = ΔL / (L0 ΔT)
C = .96 / (15.04 * 65) = 9.82 * 10^-4 / deg C
A series circuit has only one path for current,
while a parallel circuit has more than one.
m = mass of the truck = 23 00 kg
v = speed of the truck down the highway = 32 m/s
K = kinetic energy of the truck = ?
kinetic energy of the truck down the highway is given as
K = (0.5) m v²
inserting the values
K = (0.5) (2300) (32)²
K = (0.5) (2300) (1024)
K = (1150) (1024)
K = 1177600 J
hence the kinetic energy of the truck comes out to be 1177600 J
