Think about this as a table of values where domain is the x values and range is the y values.
f(4) wants the y-value when the x-value is 4
f(4) = 1/2
The second question wants us to find the x-value when f(x) also known as the y-value is 4.
f(x) = 4
x = 8
answers: 1/2, 8
The volume of the second prism is also ten times the volume of the first prism.
Let's assume that both prisms have:
width = 3 units
height = 4 units
Prism 1 length = 5 units
Prism 2 length = 50 units
Let's solve their respective volumes to compare...
Volume of prism 1 = length * width * height
= 5 * 3 * 4
= 60 units ^3
Volume of prism 2 = 50 * 3 * 4
= 600 units ^3
Prism 2/ prism 1 = 10
That means prism 2 is ten times the volume of prism 1.
Answer:
3−y
2. 8
4.2bh
Step-by-step explanation:
5(2x+y)=15
2 Divide both sides by 55.
2x+y=\frac{15}{5}2x+y=
5
15
3 Simplify \frac{15}{5}
5
15
to 33.
2x+y=32x+y=3
4 Subtract yy from both sides.
2x=3-y2x=3−y
5 Divide both sides by 22.
x=\frac{3-y}{2}x=
2
1. 3−y
2. 8
2.Add 2y2y to both sides.
x=-8+2yx=−8+2y
2 Regroup terms.
x=2y-8x=2y−8
Answer: $21
HOPE THIS HELPS
CAN U PLEASE GIVE ME BRAINLIEST
Area of circle = πr²
Area of circle = π x 12 x 12
Area of circle = 452.4cm² (nearest tenth)
