Answer:
Step-by-step explanation:
d is true
The equation formula of the circle is (x-h)^2 + (y-k)^2 = r^2
where (h,k) the point of the center of the circle
and (r) is the radius of the circle
so if the center of the circle = (-2,-4)
by subs. in the formula we get (x-(-2))^2 + (y-(-4))^2 = r^2
then the equation will be (x+2)^2 + (y+4)^2 = r^2
now we want to define the radius of the circle r
since point (3,8) lay on the circle so we can
then subs. in the equation to get the radius
(x+2)^2 +(y+4)^2 = r^2
(3+2)^2 +(8+4)^2 = r^2
25 + 144 = r^2
r^2 = 169
r= 13
the radius of the circle is 13
so by subs in the equation we get
(x+2)^2 + (y+4)^2 = 169
so it is the first answer in the choices
Answer:
$60
Step-by-step explanation:
This is because 400 times 0.03 is 12 and 12 times 5 is 60
Answer:
Possible values of dimensions are (24,16,2) or (24,8,4)
Step-by-step explanation:
We are given the volume of the Cuboid and length . We are required to find the possible values of width and height from this information.
Let us say that the width is x and height is y
Length = 24
Volume of a cuboid = length * width * height
Volume = 768
768=24*x*y
xy=32
Now the possible factors of 32
32=1*32 ( Which shall not be taken into consideration as length is already given as 24 and width or height can not be more length)
32=2*16
32=4*8
Hence the possible values width are 8, 16 and that of height 4 and 2
Hence the possible values of dimensions are (24,16,2) or (24,8,4)
Answer:
<h2><em>
2ft by 2ft by 1 ft</em></h2>
Step-by-step explanation:
Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;
S = lw+2wh+2lh ... 1
Given the volume V = lwh = 4ft³ ... 2
From equation 2;
h = 4/lw
Substituting into r[equation 1;
S = lw + 2w(4/lw)+ 2l(4/lw)
S = lw+8/l+8/w
Differentiating the resulting equation with respect to w and l will give;
dS/dw = l + (-8w⁻²)
dS/dw = l - 8/w²
Similarly,
dS/dl = w + (-8l⁻²)
dS/dw = w - 8/l²
At turning point, ds/dw = 0 and ds/dl = 0
l - 8/w² = 0 and w - 8/l² = 0
l = 8/w² and w =8/l²
l = 8/(8/l² )²
l = 8/(64/I⁴)
l = 8*l⁴/64
l = l⁴/8
8l = l⁴
l³ = 8
l = ∛8
l = 2
Hence the length of the box is 2 feet
Substituting l = 2 into the function l = 8/w² to get the eidth w
2 = 8/w²
1 = 4/w²
w² = 4
w = 2 ft
width of the cardboard is 2 ft
Since Volume = lwh
4 = 2(2)h
4 = 4h
h = 1 ft
Height of the cardboard is 1 ft
<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>
