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3 years ago

Please, someone, answer this asap; mean median mode and range:

Mathematics

2 answers:

Ne4ueva [31]3 years ago

6 0

___________________________________

hey!!

 Given data=24,31,12,38,12,15

 summation fX=132

 N(total no.of items)=6

 Now,

 Mean=summation FX/N

 =132/6

 =22

 2. Arranging the data in ascending order

 = 12,12,15,24,31,38

 N=6

 Median=(N+1/2)th item

 = (6+1/2) th item

 =(7/2)th item

 =3.5 th item

Again,

median=3 rd item + 4th item/2

 =15+24/2

 = 39/2

3.Range= highest score- lowest score

 =38- 12

 =26

4. Mode= 12 because it has more frequency.

______________________________________

<h3>Answers:</h3>

22
19.5
 26
 12
False
True
Mean
False
add the numbers and divide by the total number of numbers 
bimodal

<h2>Hope it helps...</h2>

Good luck on your assignment

Alona [7]3 years ago

5 0

Answer:

1) 22

2) 19.5

3) 26

4) 12

5) False

6) True

7) Mean

8) False

9) Add all the numbers and divide by the total number of numbers

10) Bimodal

Step-by-step explanation:

1)Use the data to calculate the mean. 24, 31, 12, 38, 12, 15 *

To calculate mean you add all the numbers up and divide by the total number of numbers.

$\frac{24 + 31+12+38+12+15}{6} = 22$

2) Use the data to calculate the median. 24, 31, 12, 38, 12, 15 *

For median, arrange the numbers from lowest to largest

12, 12, 15, 24, 31, 38

use (n+1) / 2 to figure out which value is the median

(6+1) / 2 = 3.5 (median is in between the 3rd and 4th value)

(15+24) / 2 = 19.5

3) Use the data to calculate the range. 24, 31, 12, 38, 12, 15 *

Range is max value - min value

38 is max and 12 is min

38 - 12 = 26

4) Use the data to calculate the mode. 24, 31, 12, 38, 12, 15 *

Mode is the value that appears most frequently

In this case 12 appears 2 times, therefore it is the mode

5) the mode represents the number that appears the least *

False, mode is the number that appears the most

6) To calculate the range we use the highest and lowest number ? *

True

7) Average is another word for *

mean

8) the range indicates the middle number ? *

False, range is the max value - min value

9) which statement best describes the mean. *

add all the numbers and divide by the total number of numbers

10) A data set with two modes is known as *

bimodal

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Pls answer b, confused

Andreyy89

If this is also for the inequality 4 < 8, then:

4 < 8 / /(-2)

-2 > -4

It is true, because the sign also changed.

5 0

3 years ago

Please help..!!!!!!!

Morgarella [4.7K]

Answer:

E) (-4, -3)

Step-by-step explanation:

To use elimination, you need to have one variable in both equations that have the same coefficient. (The coefficient is the number attached to the variable). Both equations have "7y".

The way elimination works is by eliminating one of the variables first. Decide how (-7y) and (-7y) can cancel out and become 0. You can either add or subtract.

(-7y) - (-7y) Try subtracting

= (-7y) + 7y

= 0

Based on this, we should subtract the whole equations.

Set up the equations like normal subtraction. Then, subtract each of the terms that have the same variable.

. 4x - 7y = 5

- 9x - 7y = -15 Do 4x - 9x = -5x. -7y - (-7y) = 0. 5 - (-15) = 20.

. -5x - 0 = 20 "y" cancelled out

. -5x = 20 Isolate 'x'

. -5x/-5 = 20/-5 Divide both sides by -5

. x = -4 Solved x-coordinate

Substitute 'x' for -4 in any of the equations. Then simplify and isolate "y" to solve for the y-coordinate.

4x - 7y = 5

4(-4) - 7y = 5 Simplify the multiplication.

-16 - 7y = 5 Start isolating 'y' now

-16 + 16 - 7y = 5 + 16 Add 16 to both sides. Left side cancels out 16

-7y = 5 + 16 Solved right side by adding

-7y = 21

-7y/-7 = 21/-7 Divide both sides by -7

y = -3 Solved y-coordinate

Therefore the answer is (-4, -3).

5 0

3 years ago

A graphing calculator is recommended. A function is given. g(x) = x4 − 5x3 − 14x2 (a) Find all the local maximum and minimum val

Taya2010 [7]

Answer:

The local maximum and minimum values are:

Local maximum

$g(0) = 0$

Local minima

$g(5.118) = -350.90$

$g(-1.368) = -9.90$

Step-by-step explanation:

Let be $g(x) = x^{4}-5\cdot x^{3}-14\cdot x^{2}$ . The determination of maxima and minima is done by using the First and Second Derivatives of the Function (First and Second Derivative Tests). First, the function can be rewritten algebraically as follows:

$g(x) = x^{2}\cdot (x^{2}-5\cdot x -14)$

Then, first and second derivatives of the function are, respectively:

First derivative

$g'(x) = 2\cdot x \cdot (x^{2}-5\cdot x -14) + x^{2}\cdot (2\cdot x -5)$

$g'(x) = 2\cdot x^{3}-10\cdot x^{2}-28\cdot x +2\cdot x^{3}-5\cdot x^{2}$

$g'(x) = 4\cdot x^{3}-15\cdot x^{2}-28\cdot x$

$g'(x) = x\cdot (4\cdot x^{2}-15\cdot x -28)$

Second derivative

$g''(x) = 12\cdot x^{2}-30\cdot x -28$

Now, let equalize the first derivative to solve and solve the resulting equation:

$x\cdot (4\cdot x^{2}-15\cdot x -28) = 0$

The second-order polynomial is now transform into a product of binomials with the help of factorization methods or by General Quadratic Formula. That is:

$x\cdot (x-5.118)\cdot (x+1.368) = 0$