Question

A balloon at 30.0°C has a volume of 222 mL. If the temperature is increased to 56.1°C and the pressure remains constant, what will the new volume be, in mL?

Answer 1

Answer:

415.15 mL

Explanation:

To solve the statement, you can use the law of Charles - Gay Lussac, which states that "the volume of gas is directly proportional to its temperature at constant pressure." Mathematically:

$\frac{V1}{T1} = \frac{V2}{T2} = Constant$

You can calculate the volume V₂ Clearing it from the equation and replacing the values granted by the statement to perform the calculation:

V₂ = V₁ x T₂ / T₁ = 222 mL x 56.1 ° C / 30.0 ° C = 415.15 mL

Therefore, the gas at 56.1 ° C will occupy a volume of 415.15 mL