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Natasha2012 [34]
2 years ago
5

Gasoline has a density of 0.7197 grams per milliliter. Calculate the mass, in grams, of a sample of gasoline with a volume of 48

.5 milliliters.​
Chemistry
1 answer:
barxatty [35]2 years ago
8 0

Answer:

34.9103 or 34.9 g

Explanation:

Remember Density is a broken heart: m/v.

In this scenario (Let x = # of grams in the sample of gasoline),

D = 0.7198 g/mL = x g / 48.5 mL

So,

(0.7198 g/mL) * (48.5 mL) = x g

x g = 34.9103 = 34.9 g (Accounting for Significant Figures)

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Which of the following intermolecular forces would affect boiling point the most?
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3 years ago
It takes 495.0 kJ of energy to remove 1 mole of electron from an atom on the surface of sodium metal. How much energy does it ta
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Answer:

\lambda=241.9\ nm

Explanation:

The work function of the sodium= 495.0 kJ/mol

It means that  

1 mole of electrons can be removed by applying of 495.0 kJ of energy.

Also,  

1 mole = 6.023\times 10^{23}\ electrons

So,  

6.023\times 10^{23} electrons can be removed by applying of 495.0 kJ of energy.

1 electron can be removed by applying of \frac {495.0}{6.023\times 10^{23}}\ kJ of energy.

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So,  

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Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

79.78\times 10^{-20}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{82.18\times 10^{-20}}

\lambda=\frac{10^{-26}\times \:19.878}{10^{-20}\times \:82.18}

\lambda=\frac{19.878}{10^6\times \:82.18}

\lambda=2.4188\times 10^{-7}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=241.9\ nm

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