From the given observations,
You can see that as the concentration is doubled, half-life is halved.
That is,half-life is inversely proportional to concentration
As t( half-life) ~ 1/a^(n-1)
For this case n = 2,second order reaction.
R = k X a^n
Using the above formula you will get the rate and rate constant.
I believe the correct answer from the choices listed above is the second option. The factor that <span> influences both solubility and the rate of dissolution would be temperature. It is the only factor from the list that affects both. Solubility is a function of temperature only while the rate of dissolution is a function of all. Hope this answers the question.</span>
Answer: The degree of compactness of a substance
Explanation:
