Answer:
as the greatest heat capacity? a. 1,000 g of water b. 1,000 g of steel c. 1 g of water d. 1 g ... +1. kvargli6h and 1 other learned from this answer. Answer: a. 1,000 g of water ... Heat capacity of steel = 0.49 J/gram^0C. Hence 1,000 g of water will have greatest heat capacity.
Explanation:
Endothermic reactions, on the other hand, absorb heat and/or light from their surroundings. For example, decomposition reactions are usually endothermic. In endothermic reactions, the products have more enthalpy than the reactants. Thus, an endothermic reaction is said to have a positive<span> enthalpy of reaction. This means that the energy required to break the bonds in the reactants is more than the energy released when new bonds form in the products; in other words, the reaction requires energy to proceed</span>
Answer:
0.508 mole
Explanation:
NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.
The number of mole present in 78.2 g of CCl₄ can be obtained as follow:
Mass of CCl₄ = 78.2 g
Molar mass of CCl₄ = 12 + (35.5×4)
= 12 + 142
= 154 g/mol
Mole of CCl₄ =?
Mole = mass / molar mass
Mole of CCl₄ = 78.2 / 154
Mole of CCl₄ = 0.508 mole
Therefore, 0.508 mole is present in 78.2 g of CCl₄
Answer:
—96.03°C
Explanation:
We'll begin by writing out the information provided by the question. This includes:
Number of mole (n) = 0.645 mole
Volume (V) = 2.00 L
Pressure (P) = 4.68 atm
Temperature (T) =?
Recall: that the gas constant = 0.082atm.L/Kmol
With the ideal gas equation PV = nRT, the temperature of the gas can be obtained as follow:
PV = nRT
4.68 x 2 = 0.645 x 0.082 x T
Divide both side 0.645 x 0.082
T = (4.68 x 2) /(0.645 x 0.082)
T = 176.97 K
Now, We can also express the temperature obtained in celsius as shown below:
Temperature (celsius) = temperature (Kelvin) - 273
Temperature (celsius) = 176.97 - 273
Temperature (celsius) = —96.03°C
The temperature of the Neon gas is
—96.03°C
Molar mass NaOH = 40.0 g/mol
Volume in liters of solution :
5 mL / 1000 => 0.005 L
number of moles :
4 / 40 => 0.1 moles
M = n / V
M = 0.1 / 0.005
= 20 mol/L or 20 M
hope this helps!
