A skydiver deploys his parachute when he is 1000m directly above his desired landing spot. He then falls through the air at a st
1 answer:
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Answer:
v_{4}= 80.92[m/s] (Heading south)
Explanation:
In order to calculate this problem, we must use the linear moment conservation principle, which tells us that the linear moment is conserved before and after the collision. In this way, we can propose an equation for the solution of the unknown.
ΣPbefore = ΣPafter
where:
P = linear momentum [kg*m/s]
Let's take the southward movement as negative and the northward movement as positive.
where:
m₁ = mass of car 1 = 14650 [kg]
v₁ = velocity of car 1 = 18 [m/s]
m₂ = mass of car 2 = 3825 [kg]
v₂ = velocity of car 2 = 11 [m/s]
v₃ = velocity of car 1 after the collison = 6 [m/s]
v₄ = velocity of car 2 after the collision [m/s]
Answer:
-2370000 N force acts on the charge particle
Explanation:
We have given electric field E = 790000 N/C
Charge
We know that force on any charge particle due to electric field is given by
, here q ia charge and E is electric field
So force
So -2370000 N force acts on the charge particle