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Katyanochek1 [597]

3 years ago

7

HELP FAST MARKING BRAINLEST A neutral electroscope is touched with a positively charged rod. After the rod is removed the electr

oscope is charged positively because of: a. Induction b. Conduction c. Photoemission d. None from the above

1 answer:

ELEN [110]3 years ago

5 0

on touching electroscope gets positively charged, so answer is B. conduction

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A mass of 148 g stretches a spring 13 cm. The mass is set in motion from its equlibrium position with a downward velocity of 10

Charra [1.4K]

Answer:

$u(t)=1.15 \sin (8.68t)cm$

0.3619sec

Explanation:

Given that

Mass,m=148 g

Length,L=13 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

$\omega_0=\sqrt{\frac{g}{L}}\\\\=\sqrt{\frac{980}{13}}\\\\=8.68 rad/s$

Where $g=980 cm/s^2$

$u(t)=Acos8.68 t+Bsin 8.68t$

u(0)=0

Substitute the value

$A=0\\u'(t)=-8.68Asin8.68t+8.68 Bcos8.86 t$

Substitute u'(0)=10

$8.68B=10$

$B=\frac{10}{8.68}=1.15$

Substitute the values

$u(t)=1.15 \sin (8.68t)cm$

Period =T = 2π/8.68

After half period

π/8.68 it returns to equilibruim

π/8.68 = 0.3619sec

6 0

3 years ago

A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as t

salantis [7]

Answer:

2.07

Explanation:

Since you didn't supply the drawing, here is what I assumed:

A is the corner opposite the axis of rotation

B is one of the remaining two corners

L1 is the side between A & B

Centripetal acceleration is given by:

ac = v^2 / r = (v / r) * (v / r) * r…………1

Also angular speed is

w = v / r,………….2

Substituting (2) in (1) gives:

ac = (v / r) * (v / r) * r……….3

= (v / r)^2 * r

= w^2 * r

Therefore, the angular acceleration at A and at B are given by:

acA = w^2 * rA……..4

acB = w^2 * rB……..5

It is given that:

acA = n * acB…………6

Substituting (4) and (5) into (6) gives:

w^2 * rA = n * w^2 * rB ……….7==>

rA = n * rB……..8

In terms of the sides L1 and L2:

rA = sqrt (L1^2 + L2^2)…….9

and

rB = L2…………10

Considering (8):

n * L2 = sqrt (L1^2 + L2^2)………11

Squaring both sides:

n^2 * L2^2 = L1^2 + L2^2……….12

Dividing by L2^2:

n^2 = L1^2 / L2^2 + L2^2 / L2^2…….13

= (L1 / L2)^2 + 1 ==>

n^2 - 1 = (L1 / L2)^2 ………14==>

L1 / L2 = sqrt (n^2 - 1) ………15

= sqrt (2.30^2 - 1)

= 2.07. . . . . . <<<=== the value of the ratio L1 / L2 when n = 2.30

8 0

3 years ago

Russia shut off the nord stream pipeline that supplies which nation with natural gas?.

Katyanochek1 [597]

Russia shut off the Nord Stream pipeline that supplies natural gas to Germany.

What is the Nord Stream pipeline?

A pair of offshore natural gas pipeline systems in Europe called Nord Stream cross the Baltic Sea from Russia to Germany. It consists of the Nord Stream 1 and Nord Stream 2 pipelines, both of which originate in northwest Russia, near Finland, in Vyborg and Ust-Luga, respectively. Both pipelines travel to Lubmin in the Mecklenburg-Vorpommern state of northeastern Germany.

Due to Russia's invasion of Ukraine, certification for Nord Stream 2 has been rejected. When referring to a larger network of pipelines, such as the feeding onshore pipeline in Russia and additional connections in Western Europe, the term "Nord Stream" is sometimes used.

Nord Stream joins the NEL pipeline to Rehden near Bremen in northwestern Germany and the OPAL pipeline to Olbernhau in eastern Germany at the Czech border in Lubmin.

Thus, the Nord Stream pipeline supplies natural gas to Germany.

Learn more about the natural gas pipeline here,

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5 0

2 years ago

What is magnification

il63 [147K]

The action or process of magnifying something or being magnified, especially visually. Hope this helped

5 0

3 years ago

Calculate the acceleration of a 1000 kg car if the motor provides a small thrust of 1000 N and the static and dynamic friction c

grin007 [14]

Explanation :

It is given that,

Mass of the car, m = 1000 kg

Force applied by the motor, $F_A=1000\ N$

The static and dynamic friction coefficient is, $\mu=0.5$

Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,

$F_A-\mu mg=ma$

$\dfrac{F_A-\mu mg}{m}=a$

$a=\dfrac{1000-0.5(1000)(9.81)}{1000}$

$a=-3.905\ m/s^2$

So, the acceleration of the car is $-3.905\ m/s^2$ . Hence, this is the required solution.

6 0

3 years ago