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horrorfan [7]
3 years ago
8

Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0

Mathematics
2 answers:
Trava [24]3 years ago
5 0

Answer:

The solution in the interval [0, 2π) of the expression (\sin x)(\cos x) = 0 are x=0,\pi,\frac{\pi}{2},\frac{3\pi}{2}                                

Step-by-step explanation:

Given : Expression (\sin x)(\cos x) = 0

To find : All the solutions in the interval [0, 2π) ?

Solution :

Expression (\sin x)(\cos x) = 0

When a\cdot b=0\Rightarrow a=0\text{ or } b=0

\sin x= 0  or \cos x= 0      

x=\sin^{-1}(0)  or x=\cos^{-1}(0)        

The general solution of the equations are

x=0,\pi,2\pi,..  or x=\frac{\pi}{2},\frac{3\pi}{2},..

From 0\leq x

The solutions are          

x=0,\pi  or x=\frac{\pi}{2},\frac{3\pi}{2}    

Therefore, The solution in the interval [0, 2π) of the expression (\sin x)(\cos x) = 0 are x=0,\pi,\frac{\pi}{2},\frac{3\pi}{2}  

Deffense [45]3 years ago
3 0
\bf sin(x)cos(x)=0\implies 
\begin{cases}
sin(x)=0\\
\measuredangle x=sin^{-1}(0)\\
\measuredangle x=0\ ,\ \pi \\
----------\\
cos(x)=0\\
\measuredangle x=cos^{-1}(0)\\
\measuredangle x=\frac{\pi }{2}\ ,\ \frac{3\pi }{2}
\end{cases}
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