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ser-zykov [4K]
3 years ago
7

Find the area of the following figure below

Mathematics
1 answer:
icang [17]3 years ago
6 0
140
explanation: ......
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The Unisphere is the world's largest man-made globe. It was built as the symbol of the 1964-1965 New York World's Fair. A sphere
Xelga [282]
\bf \textit{surface area of a sphere}\\\\
A=4\pi r^2\qquad 
\begin{cases}
r=radius=\frac{diameter}{2}\\
diameter=2r\\
----------\\
A=45,239
\end{cases}\implies 45,239=4\pi r^2

solve for "r", to see what the radius is

keep in mind that, the diameter is just "2r"
5 0
3 years ago
I’m bad at math. This looks easy but of course I have no idea
Zanzabum

Step-by-step explanation:

(this probably won't help so sorry) this is how I would do it:

6x+24 =90

90-24=66

6x= 66

66/6 =11

x=11

3 0
3 years ago
Read 2 more answers
A. Complete the chart based on the initial conditions:
Nata [24]

Answer:

a.

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

b.

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form (a,ar,ar^2,ar^3...) where a-first \ term and r-common \ ratio

#Since the population is reducing, r can is obtained as r=1-r=0.94

#The n^t^h term is obtained using the formula x_n=ar^(^n^-^1^), given a=1200

The number of ants alive after every month (in first 4 months)

Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936

The ant's alive after 4 months is obtained as the value of x_5

x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: (a,ar,ar^2,ar^3...).

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

r=1.1 and a=80 and x_n=ar^(^n^-^1^)

The population after 4weeks will be:

week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g

8 0
4 years ago
I need help ASPA with these two questions!!! <3 GIVE THANKS
cestrela7 [59]

Answer:

Part 1) Is a cubic expression

Part 2) The quadratic expression is 12x² + 8x − 1

Step-by-step explanation:

Part 1) Classify the expression: 5x³ + 2x − 3

we know that

Polynomials can be classified two different ways - by the number of terms and by their degree.

so

a) <u>By the number of terms</u> is a trinomial, because has three terms

b) <u>By their degree</u> The degree of the polynomial is found by looking at the term with the highest exponent on its variable

The highest exponent is 3 so this is a 3rd degree trinomial  

therefore

Is a cubic expression

Part 2) Choose the expression that represents a quadratic expression

we know that

If the expression is a quadratic equation , then the highest exponent of the variable is 2

therefore

The quadratic expression is 12x² + 8x − 1

6 0
3 years ago
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How do u solve 6 1/2 - 1 9/10
pishuonlain [190]
Just convert the fractions into decimals. for example, 6 1/2 equals 6.5 as a decimal. 1 9/10 would be converted to 1.9. Then just do 6.5-1.9, and that equals 4.6.
5 0
3 years ago
Read 2 more answers
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