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Wewaii [24]
4 years ago
12

1/2y-3/5=4/5 what is this?

Mathematics
1 answer:
user100 [1]4 years ago
6 0

Answer:

1 2⋅−1⋅3 5=4 5

Step-by-step explanation:

Combine multiplied terms into a single fraction

12y−1⋅35=45

\frac{1}{2}y-1 \cdot \frac{3}{5}=\frac{4}{5}

21​y−1⋅53​=54​

12−1⋅35=45

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The ratio black to blue bags is 5 to3 if there is 10 black bags how many blue bags?
konstantin123 [22]

Answer: 6

Step-by-step explanation:

6 0
3 years ago
Joe made a scale drawing of the community pool in his town. the pool has a perimeter of 77 meters, what is the length and width
viva [34]

Answer:

The length of the pool is 28 meters and the width of the pool is 10.5 meters.

Step-by-step explanation:

In the scale drawing of Joe, the community pool has (length : width) = 8 : 3

Let the actual length of the pool is 8x meters and the actual width is 3x meters.

Now, given that the actual pool has a perimeter of 77 meters.

So, 2(8x + 3x) = 77

⇒ 22x = 77

⇒ x = 3.5

So, the length of the pool is 8x = 8(3.5) = 28 meters and the width of the pool is 3x = 3(3.5) = 10.5 meters. (Answer)

8 0
3 years ago
Simplify <br> -2.5·4<br><br><br><br> thanks hhhhhhhhh
ICE Princess25 [194]

Answer:

-10

Step-by-step explanation:

-2.5 times 4

-10

4 0
3 years ago
Read 2 more answers
Please help me with this
Yuliya22 [10]
Answer is B. Bc it's 72/12 =.5
8 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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