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3 years ago

If one costs £0.05, find the cost of 100

2 answers:

7 0

This is quite simple once you understand.
Since 100 is a round number all you must do is move the 0.05 up 2 zeros.
You get the zeros from the hundreds btw.

0.05 x 100 = 5
So the answer is £5

azamat3 years ago

5 0

For find the answer we just should multiply 0.05 with 100

so 0.05×100=5 :)

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Please someone help me .I need help. Focus on number 4

eimsori [14]

Answer:

Step-by-step explanation:

To determine if the point (- 3, 5) is a solution to both equations.

Substitute the x and y values into the left side of both equations and if equal to the right sides then the point is a solution.

x - 3y = - 3 - 3(5) = - 3 - 15 = - 18 ← True

- 2x + y = - 2(- 3) + 5 = 6 + 5 = 11 ← False

Thus (- 3, 5) is not a solution to the system of equations.

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3 years ago

425 school children were surveyed about what they want to be when they grow up, out of a choice of five professions. The results

hammer [34]

Given:

425 school children

Teacher : 80
Doctor : 105
Lawyer : 70
Police Officer : 70
Firefighter : 100
Total = 425

After applying Pearson's chi-squared test, it is concluded that this data reflects a real difference in the population.

$x^{2} = summation ((O_i - E_i)^2/E_i)$

6 0

4 years ago

I think the answer is A <br><br><br> Correct?

xeze [42]

You can see that there are 6 rock CDs, over a total of

$6+10+4+8+12 = 40$

So, the ratio of rock CDs over the total number of CDs is

$\dfrac{6}{40} = 0.15$

Which is 15%.

So, yes, the answer is A

4 0

3 years ago

Read 2 more answers

A 6 sided number cube is tossed. what is the probability of rolling a 6 or an odd number?

Veronika [31]

For any probability the formula is $P_{desired}=\frac{desired}{total}$ . In this case we have 4 desired outcomes (the odds, 1, 3 and 5, and also 6) out of 6 total sides, so our probability $P_{oddor6} =\frac{odd or 6}{total sides}=\frac{4}{6} = \frac{2}{3}$ .

Mutually exclusive means the events cant occur at the same time. In our case it is not possible to roll both a 6 and an odd number at the same time since 6 is even. Therefore the events ARE mutually exclusive.

Combine the two parts and C is the correct answer. <span />

3 0

4 years ago

Three women, Chantel, Marissa, and Qian, enjoy running laps around a circular track. Each women runs at a constant speed. It tak

lubasha [3.4K]

It takes 150 seconds for Qian to complete the track.

Let she runs the track in the clockwise direction.

In 60 seconds, she runs $\frac{60}{150}$ = $\frac{2}{5}$ th of the track.

Since she meets Marissa, who is running in the opposite (counter clockwise) direction in every 60 seconds, Marissa should have completed $\frac{3}{5}$ th of the track.

Chantel meets Marissa in every 300 seconds.

So, in 60 seconds, she advances Marissa by $\frac{1}{5}$ th of the track.

Hence, in 300 seconds, Qian, Marissa and Chantel all meets at the starting point.

ALITER;

Marissa meets Qian in every 60 seconds.

So, Marissa and Qian meet each other in 60th, 120th, 180th, 240th and 300th second.

But, it is given that Chantel meets Marissa in every 300 seconds.

So, in 300 seconds, Qian, Marissa and Chantel meet each other.

6 0

3 years ago