The angle required will be given by:
x=52/5π-5*2π=2/5π
the positive angle less than one revolution around the unit circle that os co-terminal with angle of 52/5π is 2/5π
Answer:
x is 24° it is bcs triangle have at all 180°
that bigger one have 180-94-41=45° on right side
180-111-45=24° ez
Answer:
this is very simple
its 2342423424324343
Step-by-step explanation:
Answer:
x = 1/3 or -2
Step-by-step explanation:
2x^2 + 7x - 2 = - x^2 + 2x
3x^2 + 5x - 2 = 0 (use factoring)
(3x − 1)(x + 2) = 0
3x - 1 = 0 OR x + 2 = 0
3x = 1 x = - 2
x = 1/3
Can you mark as brainliest? Hope it helps by the way!
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
