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densk [106]
4 years ago
9

36+36+36+36+36 ps i know this but this is way easyer

Mathematics
1 answer:
nika2105 [10]4 years ago
5 0

<em>Answer,</em>

<h3>180</h3>

<em>-Laura :-)</em>

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Sorry i ment to put 14/15 - 1/3 then put as a fraction in simplest form
Sergio039 [100]

Answer:

Step-by-step explanation:

14/15 - 1/3

= 6/10

In simplest form

= 3/5

7 0
2 years ago
What is the number written in standard form :six million , seven hundred thousand,twenty
Luda [366]
It would be 670.002*10^4

4 0
4 years ago
What does simplify the expression mean in algebra?
Pavel [41]
Reduce the number of terms in the expression by operating on like terms 
for example
Simplify
x^2 - 3x + 4 + x^2 + 6x - 6

the like terms are the x^2 and x^2 , -3x and 6x and  4 and -6 

so we have
x^2 + x^2 - 3x + 6x + 4 - 6
= 2x^2 + 3x - 2

This is the simplified form of the original expression
5 0
3 years ago
Read 2 more answers
Esteban finds 12 baseball cards on Monday and 24 more baseball cards on Tuesday he gives some baseball cards to his sister and n
sdas [7]

Answer:

Number of cards given to sister = 35 card

Step-by-step explanation:

Find baseball card on Monday = 12

Find baseball card on Tuesday = 12 + 24 = 36

Remain baseball card = 13

Find:

Number of cards given to sister

Computation:

Number of cards given to sister = Find baseball card on Monday + Find baseball card on Tuesday - Remain baseball card

Number of cards given to sister = 12 + 36 - 13

Number of cards given to sister = 35 card

5 0
3 years ago
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6  and b = 4

The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

6 0
4 years ago
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