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densk [106]
3 years ago
9

36+36+36+36+36 ps i know this but this is way easyer

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0

<em>Answer,</em>

<h3>180</h3>

<em>-Laura :-)</em>

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What is the vertex of f (x) = 5x^2+20x-16
sergeinik [125]

Answer:

vertex = (- 2, - 36)

Step-by-step explanation:

Given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = 5x² + 20x - 16 is in standard form

with a = 5, b = 20 and c = - 16

x_{vertex} = - \frac{20}{10} = - 2

Substitute x = - 2 into f(x) for corresponding y- coordinate

f(- 2) = 5(- 2)² +20(- 2) - 16 = 20 - 40 - 16 = - 36

vertex = (- 2, - 36)



3 0
3 years ago
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I did the math and I believe the answer is, the y-intercept is 12.3.
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3 years ago
Need help ASAP. Thanks!
Jet001 [13]

Answer: 114

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The is one missing side  and to find that side you will subtract  10 from 38.

38 - 10 = 28

Now add the them.

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