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3 years ago

For which value of theta is sine theta = negative 1?

Mathematics

2 answers:

Roman55 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

$sin \theta=-1=-sin \frac{\pi }{2} =sin (\pi +\frac{\pi }{2} )=sin \frac{3 \pi }{2} \\\theta=\frac{3 \pi }{2}$

Mars2501 [29]3 years ago

3 0

Answer:

i attached the answer in a picture

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Determine the image of the given point under the indicated reflection.

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(-2,-8) is what I got after reflecting it off the y=x line.

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3 years ago

What is 1.75 divided by 5.25

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4d. Health Survey. In a survey of 1020 adults in the United States, 44% said that they wash their hands after riding public tran

AleksandrR [38]

Answer:

Discrete. See explanation below

Step-by-step explanation:

We need to remember some previous concepts:

We have two types of numerical data: Discrete and Continuous

When we say Discrete data we are refering to data that is countable or can be expressed with integers in a domain.

In the other case when we talk about continuous data we are refering to data that is continuous in a specified domain, it can contain decimals or rational numbers in the Real numbers for example.

For this special case we know that they select a sample size of n=1020 and the sample proportion of people in the United States who wash their hands after riding public transportation was 0.44 or 44% in percentage.

$\hat p = \frac{X}{1020}=0.44$

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But the number of subjects on this survey needs to be Discrete, since the possible values are 0,1,2,3,4,.....,n and never we have decimals or continuous data in order to express this.

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2 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable X represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = p = 0.03.

A random sample of n = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable X thus follows a Binomial distribution with parameters n = 10 and p = 0.03.

The probability mass function of X is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

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3 years ago