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PilotLPTM [1.2K]
2 years ago
13

the table shows the cost of the daycare for Lucy's dog this week her dog went 3 full days of day care and 2 half days of day car

e write an expression for the total cost of this week day care then evaluate the expression
Mathematics
1 answer:
drek231 [11]2 years ago
7 0

An expression for the total cost of the daycare for Lucy's dog this week is T = 3F + 2H and the total cost is equal to $114.

<h3>How to write an expression for the total cost?</h3>

In this exercise, you're required to write an expression for the total cost of the daycare for Lucy's dog this week. Thus, we would assign a variable to the cost for full-day and half-day day care as follows:

  • Let the cost for full-day be F.
  • Let the cost for half-day be H.
  • Let total cost be T.

Thus, the total cost of the daycare is given by:

T = 3F + 2H

Evaluating the expression, we have:

T = 3(28) + 2(15)

T = 84 + 30

T = $114.

Read more on expressions here: brainly.com/question/12189823

#SPJ1

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Answer: D

Step-by-step explanation:

If Joe orders 2 chicken dinners and 3 sides for $34.50, then you have to multiply 3.50 by 3 to get the ammount that the dinners cost.

3.50x3 = 10.50

Next, you have to subtract 10.50 from 34.50 to get the cost of just the 2 dinners.

34.50 - 10.50 = 24.00

Now, divide 24 by 2 to get the cost for 1 dinner.

24/2 = 12

Since Brody ordered 2 sides, you have to subtract 3.50x2 = 7 from 43 to get the total of his dinners.

43 - 7 = 36.

Now we can check our answer. Since 1 dinner costs $12, we can multiply 12 by 3 to get 36, which is the exact same number as the one we just figured out. So, each side costs 3.50.

(You can also multiply 12 by 3.50 to get 43, which was the total cost of Brody's order.)

8 0
2 years ago
6 + 3 • 4 evaluate the following numerical exspressions
Nitella [24]
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3 years ago
There are 8 midsize cars and 15 compact cars and 6 will be selected. What is the probability of selecting all midsize cars?
hodyreva [135]

Answer:

Assuming order does not matter, the probability of selecting all midsize cars is 0.000277373, or \frac{4}{14421}.

Step-by-step explanation:

First, we must find the n(Total arrangements of selections)=(8+15)C6

n(Total arrangements of selections)=23C6

n(Total arrangements of selections)=100,947

Second, we must find the n(Arrangements where all are midsize cars)=8C6

n(Arrangements where all are midsize cars)=28

To find the probability of selecting all midsize cars, we divide the n(Arrangements where all are midsize cars) by the n(Total arrangements of selections):

P(All midsize cars)= \frac{28}{100,947}

P(All midsize cars)= \frac{4}{14421}=0.000277373.

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Neko [114]

Hi there!

quarter:18

<u><em>1.Find common denominator in 4 and 1/2:</em></u>

<u><em /></u>4=\frac{1}{4}<u><em /></u>

<u><em /></u>\frac{1}{2}=\frac{2}{4}<u><em /></u>

<u><em>2.Convert 4 2/4 into mixed number:</em></u>

<u><em /></u>4\frac{2}{4}=\frac{18}{4}<u><em /></u>

<u><em>3.Divide 18/4 by 1/4:</em></u>

<u><em /></u>\frac{18}{4}*\frac{1}{4}=18<u><em /></u>

Therefore, there is 18 quarters in 4 1/2.

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