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3 years ago

8

Let f(x) = x 7 and g(x) = x − 4. find f(x) ⋅ g(x).

2 answers:

scoundrel [369]3 years ago

5 0

Answer:

x^2+3x-28

Step-by-step explanation:

(x+7)(x-4) multiply the parentheses

x^2-4x+7x-28 combine like terms

x^2+3x-28

nikklg [1K]3 years ago

4 0

F(x) = x⁷

g(x) = x - 4

f(x).g(x) = <span>x⁷*(x - 4) = x</span>⁸ - 4x⁷

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The equation of a function<br>y = 2/3x+1/3 find the value of y<br>when x = -3<br>when x = 1 1/2

kirill [66]

Answer:

$y = \frac{-5}{3}\\\\y = \frac {4}{3}$

Step-by-step explanation:

$y = \frac{2}{3} x + \frac{1}{3}\\\\when \ x = -3 \\\\y = \frac{2}{3}(-3) + \frac{1}{3} = -2 + \frac{1}{3} = \frac{-6 + 1}{3}= \frac{-5}{3} \\\\When \ x = 1 \frac{1}{2} = \frac{3}{2}\\\\y = \frac{2}{3} \times \frac{3}{2} + \frac{1}{3} = 1+ \frac{1}{3} = \frac{3 + 1}{3}= \frac{4}{3} \\\\$

5 0

3 years ago

Experimental data are collected as:

aliina [53]

Answer:

$y = 1.00114x + 1.75243$

Step-by-step explanation:

Given

The x and y values

Required

The regression line equation

Because of the length of the given data, I will run the analysis using online tools, then analyze the result.

From the analysis, we have:

$\sum x = 5050$

$\sum y = 5231.1011$

$\bar x = 50.5$

$\bar y = 52.311$

$SSX = 83325$ --- Sum of squares

$SP = 83419.7626$ --- Sum of products

The regression equation is calculated as:

$y = ax + b$

Where:

$a = \frac{SP}{SSX}$

So, we have:

$a = \frac{83419.76}{83325}$

$a = 1.00114$

$b = \bar y - a * \bar x$

$b = 52.31 - (1.00114*50.5)$

$b = 1.75243$

So:

$y = ax + b$ becomes

$y = 1.00114x + 1.75243$

6 0

3 years ago

6 fall between what two intergers

topjm [15]

Answer:

5 and 7

Step-by-step explanation:

5 and 7 are the nearest integers, and 6 is right in between them

7 0

3 years ago

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What is 7,750 to the nearest thousand

victus00 [196]

Answer:

8000

Step-by-step explanation:

7750 = 8000

thus, 7,750 to the nearest thousand is 8000

6 0

3 years ago

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Please explain how you get the answer. show work.

ladessa [460]

I think it's b okay Im sure

8 0

4 years ago

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