By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.
Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:
, where
represents the points being passed through.
Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>
You answer is the second one which is -0.8
The errors are that she is just multiplying incorrectly.
10* 1.75 = 17.5
100* 1.75= 175
1000* 1.75 = 1750
When you are multiplying by tens (hundreds and thousands are also considered tens since they are just 10*10 and 10*10*10), you should just be moving the decimal place forward one place.
This goes back to very basic math when you are learning place values.
The equation for the line will be x+2y=-20
